我試圖環繞的InnoDB的僵局,偶爾表現出來了我的頭:爲什麼InnoDB CREATE ... SELECT使用獨佔鎖?
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LATEST DETECTED DEADLOCK
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110511 10:45:59
*** (1) TRANSACTION:
TRANSACTION 0 959459752, ACTIVE 0 sec, process no 24148, OS thread id 2958613424 starting index read
mysql tables in use 16, locked 16
LOCK WAIT 2 lock struct(s), heap size 320
MySQL thread id 13029007, query id 85826239 localhost andrew updating
DELETE FROM `clients_permission_assignments` WHERE permission_assignment_id = 3761 AND client_id IN (52621)
*** (1) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 0 page no 1490959 n bits 864 index `unique_index` of table `test/clients_permission_assignments` trx id 0 959459752 lock_mode X waiting
Record lock, heap no 202 PHYSICAL RECORD: n_fields 3; compact format; info bits 32
0: len 4; hex 8000cd8d; asc ;; 1: len 4; hex 80000eb1; asc ;; 2: len 6; hex 0000006b7d5c; asc k}\;;
*** (2) TRANSACTION:
TRANSACTION 0 959459751, ACTIVE 0 sec, process no 24148, OS thread id 1996331952 fetching rows, thread declared inside InnoDB 354
mysql tables in use 16, locked 16
20 lock struct(s), heap size 2496, undo log entries 1
MySQL thread id 13019094, query id 85826237 localhost andrew Copying to tmp table
CREATE TEMPORARY TABLE tmp_tests_people_cleanup_table (SELECT unit_code FROM (
SELECT u.unit_code, COUNT(u.unit_code) AS cnt FROM staging.client_test_utilization u
LEFT JOIN permission_assignments pa ON pa.person_id =
(SELECT person_id FROM permission_assignments pa WHERE pa.id = OLD.permission_assignment_id)
LEFT JOIN permissions p ON pa.permission_id = p.id
LEFT JOIN clients_permission_assignments cpa ON cpa.permission_assignment_id = pa.id
LEFT JOIN clients c ON c.id = cpa.client_id
LEFT JOIN staging.client_test_utilization u2 ON CONCAT('C',u2.client_number) = c.number
AND u2.unit_code = u.unit_code
WHERE p.label = 'Receive Test Updates'
AND CONCAT('C',u.client_number) = (SELECT number from clients WHERE id = OLD.client_id)
AND u2.id IS NULL GROUP BY u.unit_code
) tbl
WHERE cnt = (SELECT COUNT(*) FROM permission_assignments pa
LEFT JOIN permissions p ON pa.permission_id = p.id
LEFT JOIN clients_permission_assignments cpa ON cpa.permission_assignment_id = pa.id
WHERE p.label = 'Receive Test Updates' AND pa.person_id =
(SELECT person_id FROM permission_assignments pa WHERE pa.id = OLD.permission_assignment_id))
OR (SELECT COUNT(*) FROM permission_assignments pa
LEFT JOIN permissions p ON pa.permission_id = p.id
LEFT JOIN clients_permission_assignments cpa ON cpa.permission_assignment_id = pa.id
WHERE p.label = 'Receive Test Updates' AND pa.person_id =
(SELECT person_id FROM permission_assignments pa WHERE pa.id = OLD.permission_assignment_id)) = 0)
*** (2) HOLDS THE LOCK(S):
RECORD LOCKS space id 0 page no 1490959 n bits 864 index `unique_index` of table `test/clients_permission_assignments` trx id 0 959459751 lock_mode X locks rec but not gap
Record lock, heap no 202 PHYSICAL RECORD: n_fields 3; compact format; info bits 32
0: len 4; hex 8000cd8d; asc ;; 1: len 4; hex 80000eb1; asc ;; 2: len 6; hex 0000006b7d5c; asc k}\;;
*** (2) WAITING FOR THIS LOCK TO BE GRANTED:
RECORD LOCKS space id 0 page no 1490959 n bits 864 index `unique_index` of table `test/clients_permission_assignments` trx id 0 959459751 lock mode S waiting
Record lock, heap no 202 PHYSICAL RECORD: n_fields 3; compact format; info bits 32
0: len 4; hex 8000cd8d; asc ;; 1: len 4; hex 80000eb1; asc ;; 2: len 6; hex 0000006b7d5c; asc k}\;;
*** WE ROLL BACK TRANSACTION (1)
我不知道的時候,但它似乎是INSERT ... SELECT,CREATE ... SELECT鎖定SELECT查詢中的所有表。正如你所看到的,有很多包含連接和子查詢的表。我認爲這個鎖會是一個共享(S)鎖,但是從上面的數據看來,它似乎擁有一個獨佔(X)鎖;我不明白爲什麼。
也許如果有人可以幫我計算爲什麼在CREATE ... SELECT查詢上有一個獨佔(X)鎖定,我可以試圖解決這個死鎖問題。或者,也許我可以在僵局中獲得進一步的幫助。
謝謝。
你正在使用什麼隔離級別? – 2011-05-11 23:05:00
它似乎是MySQL的默認設置(REPEATABLE READ)。我在過去使用了'SET TRANSACTION ISOLATION LEVEL READ COMMITTED;'來解決INSERT ... SELECT問題;你認爲這也會有用嗎? – 2011-05-11 23:09:21