0
我在下面有下面的代碼。我只想要一半的線程一次輸入線程函數。我如何創建一個Semaphore來阻止其他進程?當線程完成使用函數時,我將如何解除先前阻塞的進程?實現信號量
#include <iostream>
#include <unistd.h>
#include <sys/wait.h>
#include <pthread.h>
using namespace std;
#define NUM_THREADS 4
long int sharedcount;
pthread_mutex_t count_mutex;
//Function that will be run by multiple threads
//Needs to return a void pointer and if it takes arguments
//it needs to be a void pointer
void *ThreadedFunction(void *threadid)
{
int success;
long id = (long)threadid;
//Lock mutex preventing the other threads from ru nning
success = pthread_mutex_lock(&count_mutex);
cout << "Thread " << id << " beginning.\n";
for(int i = 0; i < 100000000; i++)
sharedcount++;
cout << "Thread " << id << " exiting.\n";
cout << sharedcount << endl;
//Unlock the mutex after the thread has finished running
pthread_mutex_unlock(&count_mutex);
//Kill the thread
pthread_exit(NULL);
}
int main()
{
//Initialize mutex
pthread_mutex_init(&count_mutex, NULL);
//Create an array of threads
pthread_t threads[NUM_THREADS];
int rc;
int i;
sharedcount = 0;
for(i=0; i < NUM_THREADS; i++)
{
cout << "main() : creating thread, " << i << endl;
//Create thread by storing it in a location in the array. Call the
//function for the threads to run inside. And pass the argument (if any).
//If no arguments pass NULL
rc = pthread_create(&threads[i], NULL, ThreadedFunction, (void *)i);
if (rc)
{
cout << "Error:unable to create thread," << rc << endl;
exit(-1);
}
}
//Have main thread wait for all other threads to stop running.
for(i = 0; i < NUM_THREADS; i++)
pthread_join(threads[i], NULL);
//cout << sharedcount << endl;
pthread_exit(NULL);
}
爲什麼你用'pthread'而不是'std :: thread'和'std :: mutex'? – Xirema
我們的老師在他的例子中使用了pthread,所以我在這個項目中也使用了它。 – Jose