Python構造函數與許多可選參數

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我在python中調用一個類與許多可選參數。我這樣構造構造函數的原因是因爲我想有兩種可能性來創建員工對象的實例。Python構造函數與許多可選參數

def __init__(self, ssn=None, familyssn=None, first_name=None, last_name=None, middle_name=None, email=None, mobile_phone=None, phone=None, department=None, salary=None, employee_list=None): 
    self.employee_list = employee_list or [] 

    dict_of_emp = {} 
    list_of_emp = [] 
    self.ssn = ssn 
    self.familyssn = familyssn 
    self.first_name = first_name 
    self.last_name = last_name 
    self.middle_name = middle_name 
    self.email = email 
    self.mobile_phone = mobile_phone 
    self.phone = phone 
    self.department = department 
    self.salary = salary 

    list_of_emp.append(ssn) 
    list_of_emp.append(familyssn) 
    list_of_emp.append(first_name) 
    list_of_emp.append(last_name) 
    list_of_emp.append(middle_name) 
    list_of_emp.append(email) 
    list_of_emp.append(mobile_phone) 
    list_of_emp.append(phone) 
    list_of_emp.append(department) 
    list_of_emp.append(salary) 

    #print "listi i smid: ", list_of_emp 
    Employee.empCount += 1 

    print "loop through list in constructor: ", employee_list

這是調用構造函數的唯一方法嗎？

emp = Employee(None, None, None, None, None, None, None, None, None, None, list_of_list_emp_to_register)

我覺得它相當醜陋的語法！

來源

2014-09-27 JonB

不，你並不需要所有的'None's。你應該注意關於[keyword arguments]的文檔（https://docs.python.org/2/tutorial/controlflow.html#keyword-arguments）。另外，什麼是'list_of_list_emp_to_register'？ – 2014-09-27 21:30:23

您也可以將您最後一次選擇的'employee = None'更改爲'employee = []'，儘管可能會有一些驚愕與... – Makoto 2014-09-27 21:52:10

不可以。選項，如您所說可選。因此Employee()等同於填寫所有的None。這是ssn=None等

點到指定的最後一個參數簡單地說

emp = Employee(employee_list=list_of_list_emp_to_register)

來源

2014-09-27 21:49:05 rspencer

這正是我正在尋找的，謝謝。 – JonB 2014-09-27 21:53:06

Python構造函數與許多可選參數

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