針對關聯（one-demonsional）數組的特定部分？

Question

我想嘗試換這個數組的第一個和最後一個索引的：

<?php 
$their_name = array(
     'Jim' => 'dad', 
     'Josh' => 'son', 
     'Jamie' => 'mom', 
     'Jane' => 'daughter', 
     'Jill' => 'daughter' 
); 
?> 

因此，它看起來就像這樣：

<?php 
$their_name = array(
     'Jill' => 'dad', 
     'Josh' => 'son', 
     'Jamie' => 'mom', 
     'Jane' => 'daughter', 
     'Jim' => 'daughter' 
); 
?> 

我昨晚做了類似的事情，使用這些數組：

$temp     = $user_name[0];  
$user_name[0]   = end($user_name);  
$count     = count($user_name); 
$user_name[$count-1] = $temp;    
return $user_name;        

我假設這些方法是類似的。但是，$ their_name [0]返回'J'。

謝謝！

Answer 1

這裏有一個潛在的解決方案，以您的具體問題......

$their_name = array(
    'Jim' => 'dad', 
    'Josh' => 'son', 
    'Jamie' => 'mom', 
    'Jane' => 'daughter', 
    'Jill' => 'daughter' 
); 
// rewind array pointer to first element 
reset($their_name); 
// get key name 
$firstKey = key($their_name); 
// get value and remove from array 
$firstValue = array_shift($their_name); 

// advance pointer to last element 
end($their_name); 
// get key name 
$lastKey = key($their_name); 
// get value and remove from array 
$lastValue = array_pop($their_name); 

// first element using last key and first value 
$firstElement = array($lastKey => $firstValue); 
// last element using first key and last value 
$lastElement = array($firstKey => $lastValue); 

// add them to the remaining elements 
$their_name = $firstElement + $their_name + $lastElement; 

var_dump($their_name); 
// Result: 
array(5) { 
    ["Jill"]=> 
    string(3) "dad" 
    ["Josh"]=> 
    string(3) "son" 
    ["Jamie"]=> 
    string(3) "mom" 
    ["Jane"]=> 
    string(8) "daughter" 
    ["Jim"]=> 
    string(8) "daughter" 
} 

Answer 2

這似乎令人難以置信的基礎，但是這是你問一下：

echo $their_name['Jane']; 

$their_name['Josh'] = 'son-in-law';