我是ruby的新手,我正在解決一個涉及哈希和密鑰的問題。該問題要求我實現一個接受散列作爲參數的方法#pet_types。哈希使用人們的#名稱作爲關鍵字,並且這些值是該人擁有的寵物類型的數組。我的問題是關於使用Hash#每個方法遍歷數組中的每個數字。我想知道在使用hash#each或hash.sort.each解決問題之間是否有區別? 我花了幾個小時提出了不同的解決方案,仍然找出解決以下問題的兩種方法之間有什麼不同的方法。關於在ruby中實現哈希的問題
我包括我的代碼在repl.it:https://repl.it/H0xp/6或者你可以看到如下:
# Pet Types
# ------------------------------------------------------------------------------
# Implement a method, #pet_types, that accepts a hash as an argument. The hash uses people's
# names as keys, and the values are arrays of pet types that the person owns.
# Example input:
# {
# "yi" => ["dog", "cat"],
# "cai" => ["dog", "cat", "mouse"],
# "venus" => ["mouse", "pterodactyl", "chinchilla", "cat"]
# }
def pet_types(owners_hash)
results = Hash.new {|h, k| h[k] = [ ] }
owners_hash.sort.each { |k, v| v.each { |pet| results[pet] << k } }
results
end
puts "-------Pet Types-------"
owners_1 = {
"yi" => ["cat"]
}
output_1 = {
"cat" => ["yi"]
}
owners_2 = {
"yi" => ["cat", "dog"]
}
output_2 = {
"cat" => ["yi"],
"dog" => ["yi"]
}
owners_3 = {
"yi" => ["dog", "cat"],
"cai" => ["dog", "cat", "mouse"],
"venus" => ["mouse", "pterodactyl", "chinchilla", "cat"]
}
output_3 = {
"dog" => ["cai", "yi"],
"cat" => ["cai", "venus", "yi"],
"mouse" => ["cai", "venus"],
"pterodactyl" => ["venus"],
"chinchilla" => ["venus"]
}
# method 2
# The 2nd and 3rd method should return a hash that uses the pet types as keys and the values should
# be a list of the people that own that pet type. The names in the output hash should
# be sorted alphabetically
# switched_hash = Hash.new()
# owners_hash.each do |owner, pets_array|
# pets_array.each do |pet|
# select_owners = owners_hash.select { |owner, pets_array|
owners_hash[owner].include?(pet) }
# switched_hash[pet] = select_owners.keys.sort
# end
# end
# method 3
#switched_hash
# pets = Hash.new {|h, k| h[k] = [ ] } # WORKS SAME AS: pets = Hash.new(Array.new)
# owners = owners_hash.keys.sort
# owners.each do |owner|
# owners_hash[owner].each do |pet|
# pets[pet] << owner
# end
# end
# pets
# Example output:
# output_3 = {
# "dog" => ["cai", "yi"],
# "cat" => ["cai", "venus", "yi"], ---> (sorted alphabetically!)
# "mouse" => ["cai", "venus"],
# "pterodactyl" => ["venus"],
# "chinchilla" => ["venus"]
# }
我在程序中使用的散列數據結構首先解決這個問題。然後我試着用pet_hash重寫它。而我的最終代碼如下:
def pet_types(owners_hash)
pets_hash = Hash.new { |k, v| v = [] }
owners_hash.each do |owner, pets|
pets.each do |pet|
pets_hash[pet] += [owner]
end
end
pets_hash.values.each(&:sort!)
pets_hash
end
puts "-------Pet Types-------"
owners_1 = {
"yi" => ["cat"]
}
output_1 = {
"cat" => ["yi"]
}
owners_2 = {
"yi" => ["cat", "dog"]
}
output_2 = {
"cat" => ["yi"],
"dog" => ["yi"]
}
owners_3 = {
"yi" => ["dog", "cat"],
"cai" => ["dog", "cat", "mouse"],
"venus" => ["mouse", "pterodactyl", "chinchilla", "cat"]
}
output_3 = {
"dog" => ["cai", "yi"],
"cat" => ["cai", "venus", "yi"],
"mouse" => ["cai", "venus"],
"pterodactyl" => ["venus"],
"chinchilla" => ["venus"]
}
puts pet_types(owners_1) == output_1
puts pet_types(owners_2) == output_2
puts pet_types(owners_3) == output_3
我測試了代碼,並且每個方法都通過了測試。 – DataEngineer