我得到了tomcat的8080端口和簡單的servlet運行:在URL這個小服務程序的getJSON和servlet通信錯誤
import java.io.*;
import java.text.*;
import java.util.*;
import javax.servlet.*;
import javax.servlet.http.*;
import java.awt.*;
public class MyHelloWorld extends HttpServlet {
public void doGet(HttpServletRequest request,
HttpServletResponse response)
throws IOException, ServletException
{
String data = "Hello World from servlet!";
response.setContentType("text/plain");
response.setCharacterEncoding("UTF-8");
response.getWriter().write(data);
}
}
wget的,retrives的字符串:
"Hello World from servlet!"
也web瀏覽器打印它,所以它的工作原理和Tomcat的訪問日誌顯示響應「200」
但是,當我嘗試通過我的JavaScript獲得這個字符串:
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.min.js"></script>
<script>
$.getJSON({
type: "GET", url: "http://localhost:8080/examples/MyHelloWorld",
contentType: "text/plain",
error: function(xhr, ajaxOptions, thrownError){
alert(ajaxOptions);
alert(xhr.status);
alert(thrownError);
},
processData: true,
success: function(data, textStatus, jqXHR){ alert(data); }
});
</script>
</script>
</head>
Tomcat的日誌,我可以看到響應200,但瀏覽器不顯示任何東西 - 只是沒有內容的空白頁。如果我改變getJSON
爲get
或ajax
我得到警報與:
xhr.status = 0
ajaxOptions = "error"
thrownError = empty
Web服務器是Apache和它在端口上運行80
THX的所有幫助
getJSON'方法'錯誤用法:http://api.jquery.com/jQuery.getJSON/ – Serjio 2012-08-06 14:47:00