甲骨文左聯接返回沒有行

Question

我有一個（現在徹底導出）CTE：

feature_id | function_id | group_id | subgroup_id | type_id 
1   1    null  1    null 
1   1    null  null   14 
2   1    null  5    null 
2   1    null  null   21 
3   1    null  7    null 
3   1    null  null   5 

我試圖整理在一起使用該行：

select C1.feature_id, C1.function_Id, C2.Group_ID, C3.Subgroup_ID, C4.Type_id 
from CTE C1 
left join CTE C2 
    on C1.feature_id = C2.feature_id 
    and c1.function_id = c2.function_id 
    and c2.group_id is not null 
left join CTE C3 
    on C1.feature_id = C3.feature_id 
    and c1.function_id = c3.function_id 
    and c3.subgroup_id is not null 
left join CTE C4 
    on C1.feature_id = C4.feature_id 
    and c1.function_id = c4.function_id 
    and c4.type_id is not null 

這給我0行。 ..

爲了驗證，我跑：

select * 
from CTE C1 

選擇236行

任何人都可以幫忙嗎？當然從C1行應該回來...

編輯：固定它與Oracle語法：

select C1.feature_id, C1.function_Id, C2.Group_ID, C3.Subgroup_ID, C4.Type_id 
from CTE C1, CTE C2, CTE C3, CTE C4 
where C1.feature_id = C2.feature_id(+) 
and c1.function_id = c2.function_id(+) 
and C2.group_id(+) is not null 
... 

（我討厭甲骨文語法）

Answer 1

好，解決它...

select C1.feature_id, C1.function_Id, C2.Group_ID, C3.Subgroup_ID, C4.Type_id 
from CTE C1, CTE C2, CTE C3, CTE C4 
where C1.feature_id = C2.feature_id(+) 
and c1.function_id = c2.function_id(+) 
and C2.group_id(+) is not null 
... 

（我討厭甲骨文語法）