R中的findInterval函數（設置結果）

Question

如何用我想要的數字替換findinterval函數的結果？下面是dput（）輸出：

a=c(113,113,113,113,111,111,115,116,117,118,220,220) 
b=c(113,113,113,113,111,111,115,116,117,118,220,220) 
c=c(2,2,1,1,5,1,1,2,1,1,1,4) 
d=c(2,2,12,12,15,12,12,2,12,12,12,14) 
e=c(1,1,1,1,1,2,2,2,2,2,2,3) 
f=c(20,30,25,35,45,55,60,65,70,75,75,80) 
h=c("1A","1A","2A","3A","1A","5A","4A","4A","7A","7A","9A","9A") 
i=c(12,16,17,19,20,15,18,17,17,13,14,15) 

m=data.frame(a=a,b=b,c=c,d=d,e=e,f=f,h=h,i=i) 

dput(m) 
structure(list(a = c(113, 113, 113, 113, 111, 111, 115, 116, 
117, 118, 220, 220), b = c(113, 113, 113, 113, 111, 111, 115, 
116, 117, 118, 220, 220), c = c(2, 2, 1, 1, 5, 1, 1, 2, 1, 1, 
1, 4), d = c(2, 2, 12, 12, 15, 12, 12, 2, 12, 12, 12, 14), e = c(1, 
1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3), f = c(20, 30, 25, 35, 45, 55, 
60, 65, 70, 75, 75, 80), h = structure(c(1L, 1L, 2L, 3L, 1L, 
5L, 4L, 4L, 6L, 6L, 7L, 7L), .Label = c("1A", "2A", "3A", "4A", 
"5A", "7A", "9A"), class = "factor"), i = c(12, 16, 17, 19, 20, 
15, 18, 17, 17, 13, 14, 15)), .Names = c("a", "b", "c", "d", 
"e", "f", "h", "i"), row.names = c(NA, -12L), class = "data.frame") 

set.seed(5) 
m$rand <- runif(nrow(m)) 

m[a==113,"i"] <- c(10,11,12)[1+findInterval(unlist(m[m$a==113,"rand",with=F]),c(0.25,0.50))] 

有沒有什麼簡單的方法，從具有所有這些信件在一個地方值向量繪圖。例如，對於== 113 c（0.25,0.50），values = c（10,11,12）] [for a == 111 c（0.25,0.50,0.75），values = c（1,2， 3,4）] [對於== 115 c（0.25,0.50,0.75），values = c（1,2,3,4）]都在一個表或框架中，並且每當findinterval函數被使用時從這些繪製出來？ i列應該被相關的值替換。我想要做的是從另一個文件讀取值（例如c（10,11,12）），並在需要時放入findinterval函數。

Answer 1

0和1是findInterval正在返回的內容。這一結果應該用來索引你感興趣的值嘗試：

> k[a==113,"WWW"] <- c(10,11)[1+findInterval(unlist(k[k$a==113,"rand",with=F]),c(0.45))] 
# or draw from the values vector based on your comment 
# (which should instead be an edit rather than a comment. 
values=c(10,11,12) 
k[a==113,"WWW"] <- values[1+findInterval(unlist(k[k$a==113,"rand",with=F]),c(0.45))] 
> k 
    a b c d e WWW  rand 
1: 113 2 2 1 20 10 0.2002145 
2: 113 2 2 1 30 11 0.6852186 
3: 112 1 12 1 25 17 0.9168758 
4: 114 1 12 1 35 19 0.2843995 

由於載體的基礎，而不是從零開始1，您需要將1添加到結果。