1
併爲對不起。我花了一天,無法找到解決方案。我有隱窩(驗證)一個問題,這裏是我的代碼:使用PDO準備好的語句的PHP crypt驗證錯誤
function generateHash($password, $round=10){
$salt=substr(base64_encode(openssl_random_pseudo_bytes(17)),0,22);
$salt=str_replace("+",".",$salt);
$param='$'.implode('$',array(
"2y",
str_pad($round,2,"0",STR_PAD_LEFT),
$salt
)
);
return crypt($password,$param);
}
//NOW I INSERT HASH TO DB
$input = "abc";
$hashed = generateHash($input);
$createAccount=$db->prepare("INSERT INTO account ....
':secret' => $hashed;
.....)); // Until here, no problem, $hashed can be inserted correctely into my db (password, Varchar (64)
現在註冊後,用戶喜歡登錄,這裏的問題。首先,我檢查,看看,如果我做得很好的功能
$input = "abc";
$forCheck = "abc";
$hashedHash = generateHash($input);
if (crypt($forCheck, $hashedHash) == $hashedHash) {
echo "MATCH";
}else {
echo "NOT MATCH";
}
// OUTPUT: "MATCH"
的問題在這裏:
$check=$db->prepare("SELECT id, password FROM account WHERE email = :email ");
$check->execute(array(
':email' => $user
)
);
if ($check->rowCount() <= 0) {
echo "You are not registered";
}else {
$sRow=$check->fetchAll(PDO::FETCH_ASSOC);
foreach ($sRow as $row) {
$hashedHash = generateHash($row['password']);
if (crypt($input, $hashedHash) == $hashedHash) {
echo "Passwords Matched";
}else {
echo "Passwords did not match";
}
}
}
// OUTPUT: "Passwords did not match"
任何幫助嗎?
在第一個代碼塊(INSERT位)中'createHash'應該是'generateHash'嗎? – Phil
我認爲** generateHash ** – user3281766