使用聚集和MAX函數

我在與下面的查詢問題，在SQL Server的工作。使用聚集和MAX函數

SELECT 
     emp_id= CASE employee_id 
     WHEN '' 
      THEN RTRIM(last_name) + '_' + RTRIM(first_name) 
      + '_' + RTRIM(gender) + '_' 
      + RTRIM(race_ethnicity_code) + '_' 
      + RTRIM(high_degree_code) + '_' + RTRIM(position_code) + '_' 
      + RTRIM(assignment_code) 
      ELSE employee_id 
      END , 
     last_name, first_name, 
     assign_perc, 
      assignment_num, 
     CAST((total_salary)AS NUMERIC (18,2))* CAST((assign_perc) AS NUMERIC (18,2)) AS salary, 
     total_salary 
FROM employee 
ORDER BY last_name, first_name, district_name

我的腳本是一個簡單的列提取，當emp_id爲null時，通過case語句創建一個唯一的鍵。我遇到的問題是，當這個人有多個分配時，將assign_perc與total_Salary相乘，並且當該銷售人員僅列出一次時獲得最高工資。例如 - 我的預計業績：

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約翰·史密斯是唯一被列具有一種分配的兼職工人只有一次，所以他assign_perc將小於1但我仍然需要最高的薪水，而不是總計（assign_perc * total_salary）。感謝您的幫助。

來源

2013-04-18 Tone

您的結果與SQL不一致。對於約翰史密斯，薪水和總薪水有相同的價值，但薪水應根據您的查詢0.75 * total_salary。 –

我提供的結果是我需要的。我的查詢目前正在生產（.75 * 10400）= 7800 - 約翰史密斯的薪水。 – Tone

解決方案將非常麻煩，因爲您沒有簡單的方法來確定特定員工的條目數量，而無需具體的employee_id。 – PinnyM

如上所述，這是過於凌亂，因爲你需要使用CASE語句來確定虛擬employee_id。這將是多簡單，如果你可以重構這個CASE語句到一個UDF，或者結果在表存儲在上帝的份！

要澄清一下，這是要幹什麼 - 你想加入employee表上包含了每個員工計數的表。伯爵表是這樣的：

SELECT employee_id, COUNT(*) AS employee_count 
FROM employee 
GROUP BY employee_id

將它們連接在一起，應該是這樣的：

SELECT ... 
FROM employee 
JOIN (SELECT employee_id, COUNT(*) AS employee_count 
     FROM employee 
     GROUP BY employee_id) ec 
ON employee.employee_id = ec.employee_id

你計算現在的薪水將成爲：

 CASE 
      WHEN ec.employee_count > 1 
       THEN CAST((total_salary)AS NUMERIC (18,2))* CAST((assign_perc) AS NUMERIC (18,2)) 
      ELSE total_salary 
     END AS salary,

這裏是完整的查詢

SELECT 
     CASE employee.employee_id 
     WHEN '' 
      THEN RTRIM(last_name) + '_' + RTRIM(first_name) 
      + '_' + RTRIM(gender) + '_' 
      + RTRIM(race_ethnicity_code) + '_' 
      + RTRIM(high_degree_code) + '_' + RTRIM(position_code) + '_' 
      + RTRIM(assignment_code) 
      ELSE employee.employee_id 
      END AS emp_id, 
     last_name, first_name, 
     assign_perc, 
     assignment_num, 
     CASE 
      WHEN ec.employee_count > 1 
       THEN CAST((total_salary)AS NUMERIC (18,2))* CAST((assign_perc) AS NUMERIC (18,2)) 
      ELSE total_salary 
     END AS salary, 
     total_salary 
FROM employee 
JOIN (SELECT CASE employee.employee_id 
     WHEN '' 
      THEN RTRIM(last_name) + '_' + RTRIM(first_name) 
      + '_' + RTRIM(gender) + '_' 
      + RTRIM(race_ethnicity_code) + '_' 
      + RTRIM(high_degree_code) + '_' + RTRIM(position_code) + '_' 
      + RTRIM(assignment_code) 
      ELSE employee.employee_id 
      END AS employee_id, COUNT(*) employee_count 
     FROM employee 
     GROUP BY CASE employee.employee_id 
     WHEN '' 
      THEN RTRIM(last_name) + '_' + RTRIM(first_name) 
      + '_' + RTRIM(gender) + '_' 
      + RTRIM(race_ethnicity_code) + '_' 
      + RTRIM(high_degree_code) + '_' + RTRIM(position_code) + '_' 
      + RTRIM(assignment_code) 
      ELSE employee.employee_id 
      END) ec 
    ON CASE employee.employee_id 
     WHEN '' 
      THEN RTRIM(last_name) + '_' + RTRIM(first_name) 
      + '_' + RTRIM(gender) + '_' 
      + RTRIM(race_ethnicity_code) + '_' 
      + RTRIM(high_degree_code) + '_' + RTRIM(position_code) + '_' 
      + RTRIM(assignment_code) 
      ELSE employee.employee_id 
      END = ec.employee_id 
ORDER BY last_name, first_name, district_name

012：在地方「僱員標識」的代滔天的CASE語句

來源

2013-04-18 15:41:27 PinnyM

使用聚集和MAX函數

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