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我有兩個圖像。我想從一個圖像中抓取一個區域(多邊形,而不是矩形),並將該區域複製到另一個圖像上。我怎樣才能做到這一點?這是我到目前爲止。OpenCV python從一個圖像複製多邊形到另一個圖像
import cv2
import numpy as np
#load two images
srcfilename = 'foo.jpg'
src1 = cv2.imread(srcfilename)
srcfilename = 'bar.jpg'
src2 = cv2.imread(srcfilename)
src1_mask = np.zeros(src1.shape[:-1])
#create a polygon for region of interest
poly = np.array([ [150,150], [200,100], [350,150], [350,200], [300,220], [200,200], [190,180] ], np.int32)
cv2.fillPoly(src1_mask, [poly], 255)
在這一點上我有我的兩個圖像加載,我有一個多邊形和麪具的區域。現在我不知道如何使用這個蒙版/多邊形將src1的那部分複製到src2上。
#I can also create a mask that has the same number of channels (3)
src1_mask = np.zeros(src1.shape)
#create a polygon for region of interest
poly = np.array([ [150,150], [200,100], [350,150], [350,200], [300,220], [200,200], [190,180] ], np.int32)
cv2.fillPoly(src1_mask, [poly], (255,255,255))
最後編輯
使用位運算,我已經能夠達到我想要的東西。這裏是示例代碼。
import cv2
import numpy as np
import matplotlib.pyplot as pst
#load two images
srcfilename = 'foo.jpg'
src1 = cv2.imread(srcfilename)
srcfilename = 'bar.jpg'
src2 = cv2.imread(srcfilename)
#create mask template
src1_mask = src1.copy()
src1_mask = cv2.cvtColor(src1_mask,cv2.COLOR_BGR2GRAY)
src1_mask.fill(0)
#define polygon around region
poly = np.array([ [0,0], [20,0], [65,40], [150,40], [225,5], [225,170],[120,200], [10,190] ], np.int32)
#fill polygon in mask
_ = cv2.fillPoly(src1_mask, [poly], 255)
#create region of interest
roi = src2[np.min(poly[:,1]):np.max(poly[:,1]),np.min(poly[:,0]):np.max(poly[:,0])]
mask = src1_mask[np.min(poly[:,1]):np.max(poly[:,1]),np.min(poly[:,0]):np.max(poly[:,0])]
mask_inv = cv2.bitwise_not(mask)
img1_bg = cv2.bitwise_and(roi,roi,mask = mask_inv)
src1_cut = src1[np.min(poly[:,1]):np.max(poly[:,1]),np.min(poly[:,0]):np.max(poly[:,0])]
img2_fg = cv2.bitwise_and(src1_cut,src1_cut,mask = mask)
# Put logo in ROI and modify the main image
dst = cv2.add(img1_bg,img2_fg)
src2_final = src2.copy()
src2_final[np.min(poly[:,1]):np.max(poly[:,1]),np.min(poly[:,0]):np.max(poly[:,0])] = dst
plt.imshow(cv2.cvtColor(src2_final, cv2.COLOR_BGR2RGB))