總和（情況會導致不正確的

我有一個通訊錄，包括時間每個聯繫人住在附近的長度：總和（情況會導致不正確的

ID First_Name Last_Name Neighborhood_Time 
1  John   Smith  1-2 years 
2  Mary   Jones  2-5 years 
3  Dennis  White  2-5 years 
4  Martha  Olson  5+ years 
5  Jeff   Black  5+ years 
6  Jean   Rogers  2-5 years

我想展示的時間百分比，結果是這樣的：

One_to_2_Years Two_to_5_Years  5+_Years 
     16    50     33

這是我使用的是什麼：

select 
sum(case when Neighborhoods_time ='1-2 years' then 1 else 0 end)*100/(select count(*) from contact) as One_to_2_Years,  
sum(case when Neighborhoods_time ='2-5 years' then 1 else 0 end)*100/(select count(*) from contact) as Two_to_6_Years, 
sum(case when Neighborhoods_time ='5+years' then 1 else 0 end)*100/(select count(*) from contact) as Six_to_10_Years 
    from dbo.contact

這是我的結果：

One_to_2_Years Two_to_5_Years  5+_Years 
     0    0     16 
     16    33     0 
     0    16     16

我看到每列下的數字是正確的，我有一個問題總結他們。

我錯過了什麼？

謝謝。

來源

2012-07-19 Stan

刪除組通過。 – 2012-07-19 13:42:33

你不需要在每一列使用'/（從聯繫人中選擇count（*））'，因爲你已經從聯繫人中選擇了'/ count（*）AS'' – GarethD 2012-07-19 13:48:25

感謝Nicola，你正確。 – Stan 2012-07-19 13:53:13

添加組通過Neighborhoods_time

來源

2012-07-19 13:41:52 Stan

您的查詢的基礎上，可以產生像

select 
    Neighborhood_Time, 
    100*COUNT(*)/(Select COUNT(*) from contact) as percentvalue 
from 
    contact 
group by 
    Neighborhood_Time

如果你想水平佈置，那麼你應該使用一個支點

select 
* 
from 
(
select 
    Neighborhood_Time, 
    100*COUNT(*)/(Select COUNT(*) from contact) as percentvalue 
from 
    contact 
group by 
    Neighborhood_Time 
) src 
PIVOT 
(SUM(percentvalue) for Neighborhood_Time in ([1-2 years],[2-5 years],[5+ years])) as pt

來源

2012-07-19 14:23:50 podiluska

總和（情況會導致不正確的

回答

相關問題