ceaser密碼中未定義的變量-Python

Question

import sys 
import string 

array = [] 

while True: 

input = raw_input("Please enter no more than 10 characters, one per line, and terminate the message by entering % ") 

def main(): 
    key = 3 
    message = input 
    cryptMessage = "" 
    for ch in message: 
      cryptMessage = cryptMessage + chr(ord(ch) + key) 

if input == "%" 

print array, len(array), "The coded message is:", cryptMessage 
sys.exit(1) #This tells the program to exit 
array.append(input) 
main() 

基本上我有一切按我想要的方式工作，除了以加密形式打印用戶輸入文本。它已經以常規形式打印，我希望它以常規和加密形式打印。它一直說打印行中的cryptMessage變量是未定義的。我以爲我已經在上面的代碼中定義了它，但顯然不是。我錯過了什麼？

Answer 1

我重新編寫了一段代碼。你得到一個未定義的變量錯誤的原因是因爲你在你的main()函數中定義了cryptMessage，並且除此之外不可訪問。

import sys 

# these can be declared up here 
array = [] 
key = 3 

# loop until the user tells us not to 
while True: 

    # grab the input from the user 
    input = raw_input("Please enter no more than 10 characters, one per line, and terminate the message by entering % ") 

    # the string we'll fill 
    cryptMessage = "" 

    # go over the input and 'cypher' it 
    for ch in input: 
     cryptMessage += chr(ord(ch) + key) 

    # add this line of message to the array 
    array.append(cryptMessage) 

    # when the user tells us to stop 
    if input == "%": 

     # print and break out of the while loop 
     print "The coded message is:", ' '.join(array) 
     break 

輸出：

Please enter no more than 10 characters, one per line, and terminate the message by entering % tyler 
Please enter no more than 10 characters, one per line, and terminate the message by entering % is 
Please enter no more than 10 characters, one per line, and terminate the message by entering % my 
Please enter no more than 10 characters, one per line, and terminate the message by entering % name 
Please enter no more than 10 characters, one per line, and terminate the message by entering % % 
The coded message is: w|ohu lv# p| qdph (