T-SQL - 的範圍之間過濾日期

Question

代碼：

DECLARE @T1 TABLE ([ID] INT, [WD] DATE, [SD] DATETIME, [ED] DATETIME, [Val] INT) 
INSERT INTO @T1 ([ID], [WD], [SD], [ED], [VAL]) 
VALUES (1, '2016-02-14', '2016-02-14 08:00:00', '2016-02-14 16:30:00', 12) 
     ,(1, '2016-02-14', '2016-02-16 08:00:00', '2016-02-16 16:30:00', 15) 
     ,(3, '2016-02-14', '2016-02-16 08:00:00', '2016-02-16 16:30:00', 12) 
     ,(1, '2016-02-21', '2016-02-22 08:00:00', '2016-02-22 16:30:00', 100) 
     ,(2, '2016-02-21', '2016-02-25 08:00:00', '2016-02-25 16:30:00', 124) 
     ,(3, '2016-03-20', '2016-03-21 08:00:00', '2016-03-21 16:30:00', 10) 
     ,(3, '2016-04-17', '2016-04-17 08:00:00', '2016-04-17 16:30:00', 8); 

DECLARE @StartDate DATE 
     , @EndDate DATE; 

SELECT @StartDate = MIN(WD) FROM @T1 
SELECT @EndDate = DATEADD(DAY,6,MAX(WD)) FROM @T1; 

DECLARE @T2 TABLE (D DATE) -- Table generated to get ALL dates between the minium WD (Min Sunday) and 6 days after the maximum WD (Max Sunday + 6 days to complete the week date range) 
INSERT INTO @T2 ([D]) 
SELECT DATEADD(DAY, NBR - 1, @StartDate) 
FROM (SELECT ROW_NUMBER() OVER (ORDER BY c.object_id) AS NBR 
      FROM sys.columns c 
     ) NBR 
WHERE NBR - 1 <= DATEDIFF(DAY, @StartDate, @EndDate); 

SELECT * FROM @T1; 
SELECT * FROM @T2; 

描述： @ T1是與特定日期的預填充源數據表，其中[ID] =某種類型的ID字段，[ WD] =每週的開始日期（星期日），[SD] =該[WD]星期內的一天開始，[ED] =該[WD]星期內的一天結束，[Val] = （[WD]）和MAX（[WD]）+ 6天以內的所有日期定義和填充的表格（強制使用該表格）周）

目標：

返回@ T1數據以及這些[ID]/[WD]星期的任何缺失日期。 （參見所需的輸出爲更好地理解）

期望的結果（從Excel中複製所以格式有所不同，但沒關係）

[ID][WD]  [SD]   [ED]   [Val] 
1 2/14/2016 2/14/16 8:00 2/14/16 16:30 12 
1 2/14/2016 2/15/16 00:00 2/15/16 00:00 NULL 
1 2/14/2016 2/16/16 8:00 2/16/16 16:30 15 
1 2/14/2016 2/17/16 00:00 2/17/16 00:00 NULL 
1 2/14/2016 2/18/16 00:00 2/18/16 00:00 NULL 
1 2/14/2016 2/19/16 00:00 2/19/16 00:00 NULL 
1 2/14/2016 2/20/16 00:00 2/20/16 00:00 NULL 
3 2/14/2016 2/14/16 00:00 2/14/16 00:00 NULL 
3 2/14/2016 2/15/16 00:00 2/15/16 00:00 NULL 
3 2/14/2016 2/16/16 8:00 2/16/16 16:30 12 
3 2/14/2016 2/17/16 00:00 2/17/16 00:00 NULL 
3 2/14/2016 2/18/16 00:00 2/18/16 00:00 NULL 
3 2/14/2016 2/19/16 00:00 2/19/16 00:00 NULL 
3 2/14/2016 2/20/16 00:00 2/20/16 00:00 NULL 
1 2/21/2016 2/21/16 00:00 2/21/16 00:00 NULL 
1 2/21/2016 2/22/16 8:00 2/22/16 16:30 100 
1 2/21/2016 2/23/16 00:00 2/23/16 00:00 NULL 
1 2/21/2016 2/24/16 00:00 2/24/16 00:00 NULL 
1 2/21/2016 2/25/16 00:00 2/25/16 00:00 NULL 
1 2/21/2016 2/26/16 00:00 2/26/16 00:00 NULL 
1 2/21/2016 2/27/16 00:00 2/27/16 00:00 NULL 
2 2/21/2016 2/21/16 00:00 2/21/16 00:00 NULL 
2 2/21/2016 2/22/16 00:00 2/22/16 00:00 NULL 
2 2/21/2016 2/23/16 00:00 2/23/16 00:00 NULL 
2 2/21/2016 2/24/16 00:00 2/24/16 00:00 NULL 
2 2/21/2016 2/25/16 8:00 2/25/16 16:30 124 
2 2/21/2016 2/26/16 00:00 2/26/16 00:00 NULL 
2 2/21/2016 2/27/16 00:00 2/27/16 00:00 NULL 
3 3/20/2016 3/20/16 00:00 3/20/16 00:00 NULL 
3 3/20/2016 3/21/16 8:00 3/21/16 16:30 10 
3 3/20/2016 3/22/16 00:00 3/22/16 00:00 NULL 
3 3/20/2016 3/23/16 00:00 3/23/16 00:00 NULL 
3 3/20/2016 3/24/16 00:00 3/24/16 00:00 NULL 
3 3/20/2016 3/25/16 00:00 3/25/16 00:00 NULL 
3 3/20/2016 3/26/16 00:00 3/26/16 00:00 NULL 
3 4/17/2016 4/17/16 8:00 4/17/16 16:30 8 
3 4/17/2016 4/18/16 00:00 4/18/16 00:00 NULL 
3 4/17/2016 4/19/16 00:00 4/19/16 00:00 NULL 
3 4/17/2016 4/20/16 00:00 4/20/16 00:00 NULL 
3 4/17/2016 4/21/16 00:00 4/21/16 00:00 NULL 
3 4/17/2016 4/22/16 00:00 4/22/16 00:00 NULL 
3 4/17/2016 4/23/16 00:00 4/23/16 00:00 NULL 

我使用交叉連接之類的東西，但試了沒有運氣得到所需輸出。

Answer 1

我刪除了你的@ T2，用我@ T3代替。

DECLARE @T1 TABLE ([ID] INT, [WD] DATE, [SD] DATETIME, [ED] DATETIME, [Val] INT) 
INSERT INTO @T1 ([ID], [WD], [SD], [ED], [VAL]) 
VALUES (1, '2016-02-14', '2016-02-14 08:00:00', '2016-02-14 16:30:00', 12) 
     ,(1, '2016-02-14', '2016-02-16 08:00:00', '2016-02-16 16:30:00', 15) 
     ,(3, '2016-02-14', '2016-02-16 08:00:00', '2016-02-16 16:30:00', 12) 
     ,(1, '2016-02-21', '2016-02-22 08:00:00', '2016-02-22 16:30:00', 100) 
     ,(2, '2016-02-21', '2016-02-25 08:00:00', '2016-02-25 16:30:00', 124) 
     ,(3, '2016-03-20', '2016-03-21 08:00:00', '2016-03-21 16:30:00', 10) 
     ,(3, '2016-04-17', '2016-04-17 08:00:00', '2016-04-17 16:30:00', 8); 

DECLARE @T3 TABLE ([ID] INT, [WD] DATE, [SD] DATETIME, [ED] DATETIME); 
WITH cte AS (
SELECT DISTINCT ID, WD 
FROM 
    @T1 
) 
INSERT INTO @T3 (ID, WD, SD, ED) 
SELECT ID, WD, DATEADD(DAY,n,WD), DATEADD(DAY,n,WD) 
FROM 
    cte 
    CROSS JOIN (VALUES (0),(1),(2),(3),(4),(5),(6)) AS ADDED(n); 

SELECT t3.ID, t3.WD,COALESCE(t1.SD,t3.SD) AS SD, COALESCE(t1.ED,t3.ED) AS ED, t1.Val 
FROM @T3 t3 
    LEFT JOIN @T1 t1 ON t3.ID=t1.ID AND CONVERT(DATE,t1.SD)=CONVERT(DATE,t3.SD) 

Answer 2

這將是源數據與創建的時間軸的左連接。

我無法弄清楚的ID是如何分配的，但是當我使用COALESCE來填補缺失值這個返回所需輸出（除ID）：

SELECT [t1].[ID] 
     ,COALESCE([t1].[WD], DATEADD(DAY, 1 - DATEPART(WEEKDAY, [t2].[D]), [t2].[D])) AS WD 
     ,COALESCE([t1].[SD], [t2].[D]) AS SD 
     ,COALESCE([t1].[ED], [t2].[D]) AS ED 
     ,[t1].[Val] 
FROM @T2 [t2] 
LEFT JOIN @T1 [t1] 
ON  [t2].[D] = CONVERT(DATE, [t1].[SD]);