0
的PHP/SQL調用此:的Sql未能調用領域正確
<?php
// Filter our input.
$pID = filter_input(INPUT_GET, 'pID', FILTER_SANITIZE_NUMBER_INT);
if(!$pID) {
echo "No pID specified.";
exit;
}
$username = "##";
$password = "####";
$pdo = new PDO('mysql:host=localhost;dbname=###', $username, $password);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$sth = $pdo->prepare('
SELECT name, lname, fname, picpath, email
FROM Department, Professor
WHERE pID = ?
;');
$sth->execute(array(
$pID
));
其他PHP代碼:
if($sth->rowCount() > 0) {
$row = $sth->fetch(PDO::FETCH_ASSOC);
<div class='professor_pic'>
<img src='{$row['picpath']}' />
</div><!-- /professor_pic -->
<div class='professor_desc'>
<span class='one' style='float:left; padding:5px 0 0 5px;'><strong>Department:</strong> {$row['name']} </span><br>
} else {
echo "No results.";
}
unset($sth);
?>
爲什麼的arent這兩個字段'picpath'和'name'被拉? ?它沒有拋出任何錯誤。以上是兩個數據庫字段:
您的「其他代碼」混合了PHP和HTML,因此無效。此外,你的問題沒有意義。 – 2011-04-03 21:58:10
爲什麼你有「從部門,教授」? – Khez 2011-04-03 21:59:06
您是否打擾檢查查詢是否成功? – 2011-04-03 22:07:56