表單提交表單會話後,我們可以通過會話變量保存到變量中,我們可以檢查是否正確。但是,當我檢查出來它顯示錯誤請幫我檢查我登錄時的會話錯誤
<?php
include '../includes/config.php';
if(isset($_POST['submit']))
{
$email = $_POST['email'];
$pass = $_POST['password'];
$msg = "The email or password you entered is incorrect"; //error message
//email validation
if(empty($email) || empty($pass)){
echo $msg;
header ("refresh:5; url=index.php");
exit();
}
if(!preg_match('/@/',$email)){
echo $msg;
header ("refresh:5; url=index.php");
exit();
}
//search username and password from table users
$result = mysql_query("SELECT * FROM table_users");
$fetch = mysql_fetch_array($result);
if($email == $fetch['email'] && $pass == $fetch['pass']){
session_start();
$_SESSION['email'] = $result['email'];
$_SESSION['type'] = $result['type'];
header('refresh:2; url=../panel/index.php');
echo "Logged in..";
exit();
}
else
echo $msg;
header ("refresh:5; url=index.php");
}
else
{
header('Location:../index.php');
}
?>
這是管理員密碼
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Hotel Administration</title>
<link rel="stylesheet" type="text/css" href="../../css/system.css" />
<?php
session_start();
if(!isset($_SESSION['email']))
{
die("The user must be logged in");
}
?>
</head>
<body>
我要檢查出adminpage會話一個問題..有人說會話的錯誤消息幫助我出
什麼是實際的錯誤信息使用花塊? – webnoob
我認爲你需要會話變量沒有正確設置,因爲mysqli_fetch_array期望多一個參數MYSQLI_ASSOC用於按列名稱訪問數據或另一個參數通過索引號訪問數據。 –
我得到這個會話的錯誤信息 –