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我有一個遊戲,其中兩個玩家輪流猜測一個已經隨機生成的數字。我使用的方法來控制播放器將如下:Java遊戲與玩家的死代碼
import java.util.Random;
import javax.swing.JOptionPane;
public class randomnumgame {
private static final int player1lives = 4;
private static final int player2lives = 4;
public static void main(String []args){
while(player1lives > 0 && player2lives > 0){
playerturn1();
playerturn2();
if (player1lives == 0 || player2lives == 0){
game();
}
}
}
public static void playerturn2() {
int lives = player2lives;
Random rand = new Random();
int random = rand.nextInt(250) + 1;
String player2 = JOptionPane.showInputDialog
("Please enter a number between 1 and 250, Player 2.");
int player2int = Integer.parseInt(player2);
if(player2int == random){
JOptionPane.showMessageDialog(null, "Player 2 has guessed correctly. You have " +lives+ " lives left");
}
lives--;
JOptionPane.showMessageDialog(null, "Your guess was wrong. The actual number was: " +random+ " You have " +lives+ " left");
}
public static void playerturn1() {
int lives = player1lives;
Random rand = new Random();
int random = rand.nextInt(250) + 1;
String player1 = JOptionPane.showInputDialog
("Please enter a number between 1 and 250, Player 1.");
int player1int = Integer.parseInt(player1);
if(player1int == random){
JOptionPane.showMessageDialog(null, "Player 1 has guessed correctly. You have " +lives+ " lives left");
}
lives--;
JOptionPane.showMessageDialog(null, "Your guess was wrong. The actual number was: " +random+ " You have " +lives+ " lives left");
}
private static void game(){
if(player1lives == 0){
JOptionPane.showMessageDialog(null, "Player 2 has won the game.");
System.exit(0);
}
if(player2lives == 0){
JOptionPane.showMessageDialog(null, "Player 1 has won the game.");
System.exit(0);
}
}
}
的問題是,該代碼被標記爲在Eclipse死代碼:
if (player1lives == 0 || player2lives == 0){
game();
}
和:
private static void game(){
if(player1lives == 0){
JOptionPane.showMessageDialog(null, "Player 2 has won the game.");
System.exit(0);
}
if(player2lives == 0){
JOptionPane.showMessageDialog(null, "Player 1 has won the game.");
System.exit(0);
}
我發現了類似的問題,但不能將它們應用於這個特定的應用程序。任何幫助,將不勝感激。
提示:瞭解Java的命名約定。方法名稱go camelCase。所以變量名稱! – GhostCat