sql組合兩個子查詢並總計總計

Question

我有兩個查詢。都返回

select sum (Amount) as 'Less then 30 days', [Fluids Management$Cust_ Ledger Entry].[Customer No_] 
FROM [Fluids Management$Detailed Cust_ Ledg_ Entry] 
group by [Fluids Management$Cust_ Ledger Entry].[Customer No_] 


select sum ([Debit Amount]) as 'Less then 30 days', [Fluids Management$Cust_ Ledger Entry].[Customer No_] 
FROM [Fluids Management$Detailed Cust_ Ledg_ Entry] 
    group by [Fluids Management$Cust_ Ledger Entry].[Customer No_] 

都有更深入的標準，我只是沒有包括它。無論如何，我想採取第一個查詢，並檢查客戶不存在第二個查詢。如果是這樣，則將該金額的總和加到借方金額上。如果第二個查詢中沒有出現該id，則只需返回第一個查詢中的總和即可。其全部由顧客編號。請幫助

Answer 1

的eaiset方式可能會在一個內聯UNION查詢SUM

SELECT SUM (AMOUNT), [Customer No_] 
FROM 

(
select Amount 
      [Fluids Management$Cust_ Ledger Entry].[Customer No_] 
FROM 
     [Fluids Management$Detailed Cust_ Ledg_ Entry] 
UNION ALL 
select [Debit Amount] as 'Less then 30 days', 
     [Fluids Management$Cust_ Ledger Entry].[Customer No_] 
FROM [Fluids Management$Detailed Cust_ Ledg_ Entry] 
) 

GROUP BY [Customer No_] 

您沒有指定的數據庫，所以你可能需要別名才能線視圖，它的工作

Answer 2

放入派生表和LEFT兩個查詢加入他們的行列：

SELECT a.[Customer No_], a.'Less then 30 days' + COALESCE(b.'Less then 30 days', 0) 
FROM 
(
    SELECT SUM (Amount) AS 'Less then 30 days', [Fluids Management$Cust_ Ledger Entry].[Customer No_] 
    FROM [Fluids Management$Detailed Cust_ Ledg_ Entry] 
    GROUP BY [Fluids Management$Cust_ Ledger Entry].[Customer No_] 
) AS a 
LEFT JOIN 
(
    SELECT SUM ([Debit Amount]) AS 'Less then 30 days', [Fluids Management$Cust_ Ledger Entry].[Customer No_] 
    FROM [Fluids Management$Detailed Cust_ Ledg_ Entry] 
    GROUP BY [Fluids Management$Cust_ Ledger Entry].[Customer No_] 
) AS b 
ON a.[Customer No_] = b.[Customer No_] 

但是當你訪問同一個表兩次您可能能夠使用SUM（CASE）將其更改爲單查詢