SQL - 通過下面的查詢總計

Question

分組結果給了我兩列的輸出：

Day Num_Users_Retained 
0 209312 
1 22139 
2 11457 

等等，所有的。不過我想天的方式爲259（每天在2012年） 0將num_users_retained中所有值的總和包含在0到259之間，然後我希望第1天包含1-259中所有值的總和，依此類推，直到我到達最後一天。這裏是原來的查詢：

--Retention since January 1,2012-- 
select retention as Day,count(retention) as Num_Users_Retained 
from (select player_id,round(init_dtime-create_dtime,0) as retention 
from player 
where Trunc(Create_Dtime) >= To_Date('2012-jan-01','yyyy-mon-dd') 
and init_dtime is not null) 
Group by retention 
order by 1 

有什麼建議嗎？

Answer 1

select retention as Day 
    , Sum(count(retention)) over(order by retention desc) as Num_Users_Retained 
from (select player_id 
      , round(init_dtime-create_dtime,0) as retention 
     from player 
     where Trunc(Create_Dtime) >= To_Date('2012-jan-01','yyyy-mon-dd') 
     and init_dtime is not null 
     ) 
Group by retention 
order by retention 

Answer 2

使用分析功能

select 
    day, 
    num_users_retained, 
    sum(num_users_retained) over (order by day) as total_num_users_retained 
from churn 

http://www.sqlfiddle.com/#!4/24e02/1

此查詢寫在你的結果集。您可能可以將其應用於原始查詢。