我建議
n = sort(union(names(row1),names(row2)))
rbind(row1[n], row2[n])
# a b c <NA>
# [1,] "a1" "b1" "c1" NA
# [2,] "a1" "b2" "c2" "d1"
如果多行參與其中,你可以做
myrows = list(row1,row2)
n = sort(Reduce(union, lapply(myrows, "names")))
do.call(rbind, lapply(myrows, `[`, n))
。
問題標記爲data.frame,但該示例使用矩陣。隨着data.frames,我會用這些軟件包之一:
# new example
r1<-data.frame(a="a1",b="b1",c="c1", stringsAsFactors=FALSE)
r2<-data.frame(a="a1",d="d1",b="b2",c="c2", stringsAsFactors=FALSE)
library(data.table)
rbindlist(list(r1,r2), fill=TRUE)
# a b c d
# 1: a1 b1 c1 NA
# 2: a1 b2 c2 d1
library(dplyr)
bind_rows(r1, r2)
# a b c d
# (chr) (chr) (chr) (chr)
# 1 a1 b1 c1 NA
# 2 a1 b2 c2 d1
同樣,如果許多行參與,rs = list(r1,r2)
,你可以做rbindlist(rs, fill=TRUE)
或do.call(bind_rows, rs)
。