使用縮放對象

Question

我獲得了R和不知道這個列表中的對象我怎樣才能將它傳遞到規模

str(ss) 
    chr [1:11600, 1:2] "1_1" "1_2" "1_3" "1_4" "1_5" "1_6" "1_7" "1_8" "1_9" "1_10" "1_11" "1_12" "1_13" "1_14" "1_15" ... 
    - attr(*, "dimnames")=List of 2 
     ..$ : chr [1:11600] "features" "features" "features" "features" ... 
     ..$ : chr [1:2] "driver_trip" "prob" 

    > ss[1:10,] 
      driver_trip prob     
    features "1_1"  "0.0438400073093713" 
    features "1_2"  "0.0750898149841077" 
    features "1_3"  "0.108603234710245" 
    features "1_4"  "0.110244641673752" 
    features "1_5"  "0.114281674309826" 
    features "1_6"  "0.114693039193982" 
    features "1_7"  "0.11141782609152" 
    features "1_8"  "0.102231988595076" 
    features "1_9"  "0.1145982975793" 
    features "1_10"  "0.112394651156342" 
    > 

我嘗試介於0概率比例& 1與中心0.5

> ss.prob2<-scale(ss[,2],center=0.5) 
Error in FUN(x, aperm(array(STATS, dims[perm]), order(perm)), ...) : 
    non-numeric argument to binary operator 

Answer 1

你prob變量是字符。您可以轉換爲數據幀，因爲矩陣具有相同類型的元素（請注意，我僅使用rnorm作爲示例）：

> x <- matrix(c(paste0(1, "_", 1:10), rnorm(10)), ncol = 2) 
> x 
     [,1] [,2]     
[1,] "1_1" "-0.764003122485116" 
[2,] "1_2" "0.386744103161948" 
[3,] "1_3" "0.315941360908671" 
[4,] "1_4" "-1.17011716847999" 
[5,] "1_5" "-1.15084481612952" 
[6,] "1_6" "-0.42540116009025" 
[7,] "1_7" "0.243829019189806" 
[8,] "1_8" "-0.580361465305665" 
[9,] "1_9" "-0.575600440871097" 
[10,] "1_10" "0.633960614660247" 
> xdf <- as.data.frame(x, stringsAsFactors = FALSE) 
> str(xdf) 
'data.frame': 10 obs. of 2 variables: 
$ V1: chr "1_1" "1_2" "1_3" "1_4" ... 
$ V2: chr "-0.764003122485116" "0.386744103161948" "0.315941360908671" "-1.17011716847999" ... 
> xdf$V2 <- as.numeric(xdf$V2) 
> scale(xdf$V2, center = .5) 
      [,1] 
[1,] -1.1745529 
[2,] -0.1052411 
[3,] -0.1710333 
[4,] -1.5519273 
[5,] -1.5340188 
[6,] -0.8599129 
[7,] -0.2380424 
[8,] -1.0039071 
[9,] -0.9994830 
[10,] 0.1244806 
attr(,"scaled:center") 
[1] 0.5 
attr(,"scaled:scale") 
[1] 1.076157