獲取cellid，lac，MCC，MNC在c＃中的緯度和經度，用於控制檯或wpf應用程序

Question

我正在創建一個獲取cellid，MCC，MNC和LAC的系統，並且我想使用opencellid來獲取緯度和經度這些信息，我沒有在互聯網上找到資源，所以我不知道從哪裏開始。如果你能幫助我找到如何做到這一點，或者給我一個替代解決方案來從這些信息中找到經度和緯度，這將是很好的。由於

Answer 1

你可以在這裏找到API的信息： http://wiki.opencellid.org/wiki/API

Answer 2

檢查下面的代碼，我希望這是很有幫助的:)

using System; 
using System.Collections.Generic; 
using System.Linq; 

using System.Text; 
using System.IO; 
using System.Net; 

namespace ConsoleApplication1 
{ 
    public class GoogleMapsApi 
    { 
     static byte[] PostData(int MCC, int MNC, int LAC, int CID) 
     { 

     /* The shortCID parameter follows heuristic experiences: 

     * Sometimes UMTS CIDs are build up from the original GSM CID (lower 4 hex digits) 

     * and the RNC-ID left shifted into the upper 4 digits. 

     */ 

     byte[] pd = new byte[] { 

    0x00, 0x0e, 

    0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 0x00, 

    0x00, 0x00, 

    0x00, 0x00, 

    0x00, 0x00, 

    0x1b, 

    0x00, 0x00, 0x00, 0x00, // Offset 0x11 

    0x00, 0x00, 0x00, 0x00, // Offset 0x15 

    0x00, 0x00, 0x00, 0x00, // Offset 0x19 

    0x00, 0x00, 

    0x00, 0x00, 0x00, 0x00, // Offset 0x1f 

    0x00, 0x00, 0x00, 0x00, // Offset 0x23 

    0x00, 0x00, 0x00, 0x00, // Offset 0x27 

    0x00, 0x00, 0x00, 0x00, // Offset 0x2b 

    0xff, 0xff, 0xff, 0xff, 

    0x00, 0x00, 0x00, 0x00 

}; 
     Console.WriteLine(pd.Length); 

     bool isUMTSCell = ((Int64)CID > 65535); 

     /* if (shortCID) 

       CID &= 0xFFFF;  /* Attempt to resolve the cell using the 

          GSM CID part */ 

     if ((Int64)CID > 65536) /* GSM: 4 hex digits, UTMS: 6 hex 

         digits */ 

      pd[0x1c] = 5; 

     else 

      pd[0x1c] = 3; 

     pd[0x11] = (byte)((MNC >> 24) & 0xFF); 

     pd[0x12] = (byte)((MNC >> 16) & 0xFF); 

     pd[0x13] = (byte)((MNC >> 8) & 0xFF); 

     pd[0x14] = (byte)((MNC >> 0) & 0xFF); 

     pd[0x15] = (byte)((MCC >> 24) & 0xFF); 

     pd[0x16] = (byte)((MCC >> 16) & 0xFF); 

     pd[0x17] = (byte)((MCC >> 8) & 0xFF); 

     pd[0x18] = (byte)((MCC >> 0) & 0xFF); 

     pd[0x27] = (byte)((MNC >> 24) & 0xFF); 

     pd[0x28] = (byte)((MNC >> 16) & 0xFF); 

     pd[0x29] = (byte)((MNC >> 8) & 0xFF); 

     pd[0x2a] = (byte)((MNC >> 0) & 0xFF); 

     pd[0x2b] = (byte)((MCC >> 24) & 0xFF); 

     pd[0x2c] = (byte)((MCC >> 16) & 0xFF); 

     pd[0x2d] = (byte)((MCC >> 8) & 0xFF); 

     pd[0x2e] = (byte)((MCC >> 0) & 0xFF); 

     pd[0x1f] = (byte)((CID >> 24) & 0xFF); 

     pd[0x20] = (byte)((CID >> 16) & 0xFF); 

     pd[0x21] = (byte)((CID >> 8) & 0xFF); 

     pd[0x22] = (byte)((CID >> 0) & 0xFF); 

     pd[0x23] = (byte)((LAC >> 24) & 0xFF); 

     pd[0x24] = (byte)((LAC >> 16) & 0xFF); 

     pd[0x25] = (byte)((LAC >> 8) & 0xFF); 

     pd[0x26] = (byte)((LAC >> 0) & 0xFF); 

     return pd; 

    } 

    static public string[] GetLatLng(int MCC, int MNC, int LAC, int CID) 
    { 

     string[] result = new string[2]; 

     try 
     { 

      String url = "http://www.google.com/glm/mmap"; 

      HttpWebRequest req = (HttpWebRequest)WebRequest.Create(

       new Uri(url)); 

      req.Method = "POST"; 

      byte[] pd = PostData(MCC, MNC, LAC, CID); 

      req.ContentLength = pd.Length; 

      req.ContentType = "application/binary"; 

      Stream outputStream = req.GetRequestStream(); 

      outputStream.Write(pd, 0, pd.Length); 

      outputStream.Close(); 

      HttpWebResponse res = (HttpWebResponse)req.GetResponse(); 

      byte[] ps = new byte[res.ContentLength]; 

      int totalBytesRead = 0; 

      while (totalBytesRead < ps.Length) 
      { 

       totalBytesRead += res.GetResponseStream().Read(

        ps, totalBytesRead, ps.Length - totalBytesRead); 

      } 

      //for(int i=0;i<ps.Length;i++) 
      // Console.WriteLine(ps[i]); 
      string r = System.Text.Encoding.UTF8.GetString(ps); 
      Console.WriteLine(r); 



      if (res.StatusCode == HttpStatusCode.OK) 
      { 

       short opcode1 = (short)(ps[0] << 8 | ps[1]); 

       byte opcode2 = ps[2]; 

       int ret_code = (int)((ps[3] << 24) | (ps[4] << 16) | 

           (ps[5] << 8) | (ps[6])); 

       if (ret_code == 0) 
       { 

        double lat = ((double)((ps[7] << 24) | (ps[8] << 16) 

           | (ps[9] << 8) | (ps[10])))/1000000; 

        double lon = ((double)((ps[11] << 24) | (ps[12] << 

           16) | (ps[13] << 8) | (ps[14])))/

           1000000; 

        result[0] = lat.ToString(); 
        result[1] = lon.ToString(); 
        return result; 

       } 

       else 
       { 

        return result; 
       } 

      } 

      else 

       return result; 

     } 

     catch (Exception ex) 
     { 
      result[0] = ex.Message; 
      return result; 

     } 

    } 
} 
}