找到最常見的價值和它的順序

Question

+-----------------------+------------------------+ 
| being_followed  | follower    | 
+-----------------------+------------------------+ 
| Bob Dylan    |      B | 
| Bob Dylan    |      A | 
| Sam Cooke    |      X | 
| The Beatles   |      Y | 
| Bob Dylan    |      M | 
| Sam Cooke    |      N | 
+-----------------------+------------------------+ 

現在，我想找到哪個是being_followed最經常發生的價值，然後命令它。 它看起來有點像 -

Bob Dylan - 3 
Sam Cooke - 2 
The Beatles - 1 

請不要將此標記爲重複。

Answer 1

試試這個： -

select being_followed,count(*) total_followers 
from table 
group by being_followed 
order by total_followers desc 

Answer 2

嘗試以下：

select being_followed , count(1) as count 
from table 
group by being_followed 
order by count desc ; 

Answer 3

SELECT being_followed , count(being_followed)as counter FROM `table_Name` GROUP BY being_followed ORDER BY counter DESC 

你會得到結果，您使用組由您將獲得獨特的價值和使用count你會want.Here什麼得到相同的計數器being_followed

Answer 4

試試這個：

SELECT being_followed,COUNT(*) AS follower 
FROM tablename GROUP BY being_followed ORDER BY follower DESC; 

輸出：

+-----------------------+------------------------+ 
| being_followed  | follower    | 
+-----------------------+------------------------+ 
| Bob Dylan    |      3 | 
| Sam Cooke    |      2 | 
| The Beatles   |      1 | 
+-----------------------+------------------------+ 

Answer 5

嘗試的being_followed這

SELECT being_followed,COUNT(1) count_followers 
FROM table 
GROUP BY being_followed 
ORDER BY COUNT(1) DESC; 

獲取計數，也爲了通過從高到低基地（降序）

Answer 6

也許你可以試試這個：

select being_followed, count(*) follower 
from TableName 
group by being_followed 
order by follower desc 

它工作正常。