Oracle Sql查詢按分組劃分

MY_TABLE =帶2列的表格數字，城市。
所需輸出=城市和與城市相關的唯一編號的數量。西雅圖，貝爾維尤是Combined的一部分。即使有4個關聯到西雅圖號碼，貝爾維尤的輸出爲3，因爲只有3個不同的號碼 - 123，456，786Oracle Sql查詢按分組劃分

MY_TABLE 
Number City 
123 Seattle 
456 Bellevue 
789 LosAngeles 
780 LosAngeles 
123 Bellevue 
786 Bellevue

所需的輸出：

Combined 3 
LosAngeles 2

查詢到目前爲止：

SELECT NUMBER, CITY FROM MY_TABLE WHERE LOOKUP_ID=100 AND CITY IN 
('Seattle', 'Bellevue', 'LosAngeles') 
GROUP BY NUMBER, CITY

如果有人提供相同的建議，我將非常感激。

來源

2012-03-31 John C

你可以做類似

SELECT (case when city IN ('Seattle', 'Bellevue') 
      then 'Combined' 
      else city 
      end) city, 
     count(distinct number) 
    FROM my_table 
WHERE lookup_id = 100 
    AND city IN ('Seattle', 'Bellevue', 'LosAngeles') 
GROUP BY (case when city IN ('Seattle', 'Bellevue') 
       then 'Combined' 
       else city 
      end)

當然，我的猜測是，你有一些其他的表，告訴你哪個CITY值需要進行組合，而不是使用硬編碼CASE聲明。

來源

2012-03-31 21:41:46

試試這個：

SELECT 
    (CASE CITY 
    WHEN 'Seattle' THEN ‘Combined’ 
    WHEN 'Bellevue' THEN ‘Combined’ 
    ELSE CITY 
    END), COUNT(*) 
FROM 
    MY_TABLE 
WHERE 
    LOOKUP_ID=100 AND CITY IN ('Seattle', 'Bellevue', 'LosAngeles') 
GROUP BY 
    NUMBER, 
    (CASE CITY 
    WHEN 'Seattle' THEN ‘Combined’ 
    WHEN 'Bellevue' THEN ‘Combined’ 
    ELSE CITY 
    END)

應該做你問什麼，但我懷疑你有你定義一些其他表哪些城市應被視爲是相同的，在這種情況下，你需要加入這些表

來源

2012-03-31 21:37:23 MiMo

with t as (
SELECT (
     case when city IN ('Seattle', 'Bellevue') 
     then 'Combined' 
     else city 
     end 
    ) city, number from my_table 
) 
select city, count(distinct number) from t 
group by city

泰爾請，如果它是有用的

來源

2012-03-31 22:04:29 golgofa

這是，謝謝！ – 2012-04-01 01:03:09

有3個答案已經和他們都不是通用的更多城市。試試這個：

SELECT City, COUNT(Number) AS ExclusiveNumbers 
FROM (SELECT q2.City, q2.CityNumCount, b.Number 
     FROM MY_Table b INNER JOIN 
      (SELECT c.City, MAX(NumOccurs) AS CityNumCount 
      FROM My_Table c INNER JOIN 
          (SELECT Number, COUNT(City) AS NumOccurs 
           FROM My_Table 
           GROUP BY Number) q1 ON c.Number = q1.Number 
      GROUP BY c.City) q2 ON b.City = q2.City) q3 
WHERE CityNumCount = 1 
GROUP BY City 
UNION 
SELECT 'Combined', COUNT(DISTINCT Number) 
FROM (SELECT q2.City, q2.CityNumCount, b.Number 
     FROM MY_Table b INNER JOIN 
      (SELECT c.City, MAX(NumOccurs) AS CityNumCount 
      FROM My_Table c INNER JOIN 
          (SELECT Number, COUNT(City) AS NumOccurs 
           FROM My_Table 
           GROUP BY Number) q1 ON c.Number = q1.Number 
      GROUP BY c.City) q2 ON b.City = q2.City) q3 
WHERE CityNumCount > 1

工會的上半部分的作品出來，對於沒有共同的數字與其他任何城市，有多少不同的號碼都有每個城市的名字。
下半部分計算出與其他城市有共同數字的城市的不同數量。這兩個數字將始終合計爲原始表格中不同數字的計數。

來源

2012-03-31 22:36:46 Morbo

Oracle Sql查詢按分組劃分

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