Mysql計數和拆分爲DAY，WEEK，YEAR查看統計數據在同一查詢中

Question

我想獲取統計信息。

我正在努力爲今天，本週，本月計數。

我的查詢：

"SELECT COUNT(id) FROM images i WHERE i.user_id = 3 GROUP BY DAY(i.created_at), WEEK(i.created_at), MONTH(i.created_at)" 

輸出：

array(7) { 
    [0]=> 
    array(1) { 
    ["COUNT(id)"]=> 
    string(1) "1" 
    } 
    [1]=> 
    array(1) { 
    ["COUNT(id)"]=> 
    string(1) "1" 
    } 
    [2]=> 
    array(1) { 
    ["COUNT(id)"]=> 
    string(1) "5" 
    } 
    [3]=> 
    array(1) { 
    ["COUNT(id)"]=> 
    string(1) "5" 
    } 
    [4]=> 
    array(1) { 
    ["COUNT(id)"]=> 
    string(1) "7" 
    } 
    [5]=> 
    array(1) { 
    ["COUNT(id)"]=> 
    string(2) "17" 
    } 
    [6]=> 
    array(1) { 
    ["COUNT(id)"]=> 
    string(1) "1" 
    } 
} 

但我想分裂，如：

day = 5, 
week = 15, 
month = 67 

怎麼會呢？

---

完整的工作查詢：

SELECT 
       COUNT(i.id) AS `all`, 
       (
        SELECT 
         COUNT(id) 
        FROM 
         images 
        WHERE 
         user_id = i.user_id AND WEEK(created_at) = WEEK(NOW()) 
       ) 
       AS `week`, 
       (
        SELECT 
         COUNT(id) 
        FROM 
         images 
        WHERE 
         user_id = i.user_id AND MONTH(created_at) = MONTH(NOW()) 
       ) 
       AS `month`, 
       (
        SELECT 
         COUNT(id) 
        FROM 
         images 
        WHERE 
         user_id = i.user_id AND DAY(created_at) = DAY(NOW()) 
       ) 
       AS `day` 
      FROM 
       images i 
      WHERE 
       i.user_id = " . $user->getId() 

Answer 1

如果我理解你的權利，這應該是你在找什麼

SELECT Count(*)       AS day, 
     (SELECT Count(*) 
     FROM images 
     WHERE user_id = i.user_id 
       AND Week(i.created_at) = Week(Now()) 
     GROUP BY Week(i.created_at)) AS week, 
     (SELECT Count(*) 
     FROM images 
     WHERE user_id = i.user_id 
       AND Month(i.created_at) = Month(Now()) 
     GROUP BY Month(i.created_at)) AS month 
FROM images i 
WHERE i.user_id = 3 
     AND Day(i.created_at) = Day(Now()) 
GROUP BY Day(i.created_at)