警告：mysql_fetch_assoc（）預計參數1是資源，布爾在

Question

給我總是當我運行我的代碼

0: 
Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\fyp\admin_vieworders_details.php on line 12 
Query Failed!You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1 

這裏得到這個錯誤是我的數據庫

表order_detail {Order_Detail_ID（PK） ，Order_Quantity，SUB_TOTAL}

表順序{Order_ID上，order_date的，Order_Time，Delivery_Charge，Delivery_Name}

這裏是我的代碼

$orderid =@$_GET["id"]; 
$detail = "SELECT 
       order.*, 
       order_detail.Order_Quantity, 
       order_detail.Sub_Total 
      FROM `order` AS a, `order_detail` AS b 
      WHERE order_detail.Order_ID = `order`.Order_ID AND order_detail.Order_Detail_ID=$orderid"; 

$result = mysql_query($detail); 
$row = mysql_fetch_assoc($result); 

     if($result === FALSE) 
    { 
      die("Query Failed!".mysql_error().$result); 
    } 

Answer 1

檢查mysql_error()在致電mysql_fetch_assoc()之前。您的查詢失敗，查詢功能返回false。

$result = mysql_query($detail); 
if (!$result) { 
    die("Error: ".mysql_error()); // Note: raw database errors are useless for users 
            // better log the error an create a "nice" error page 
} 
$row = mysql_fetch_assoc($result); 

或者這樣可能會讓你開始。

Answer 2

你似乎在你的查詢時出現錯誤：

嘗試：的

$detail = "SELECT 
       a.*, 
       b.Order_Quantity, 
       b.Sub_Total 
      FROM `order` AS a, `order_detail` AS b 
      WHERE b.Order_Detail_ID = a.Order_ID AND 
        b.Order_Detail_ID=$orderid"; 

代替

$detail = "SELECT 
       order.*, 
       order_detail.Order_Quantity, 
       order_detail.Sub_Total 
      FROM `order` AS a, `order_detail` AS b 
      WHERE order_detail.Order_ID = `order`.Order_ID AND 
        order_detail.Order_Detail_ID=$orderid"; 

而且還...

$orderid =$_GET["orderid"]; 

代替

$orderid =@$_GET["id"]; 

Answer 3

改變這種

$orderid =@$_GET["id"]; 

到

$orderid =$_GET['id'];