爲什麼accept（）（用於套接字連接）會導致我的代碼被阻塞？

Question

當我運行代碼，它似乎並沒有跑整個主功能時，這條線

connect_sock = accept(sock, (struct sockaddr *)&serv_name, &len); 

是它。它甚至不會在開始時打印第一個cout，但是當我評論它時它工作正常，有人可以告訴我這個的原因嗎？

#include <sys/types.h> 
#include <unistd.h> 
#include <stdio.h> 
#include <string.h> 
#include <stdlib.h> 
#include <signal.h> 
#include <sys/socket.h> 
#include <sys/un.h> 
#include <netinet/in.h> 
#include <iostream> 

#define PORT 1227 
#define SIM_LENGTH 10; 
using namespace std; 
void clean_up(int cond, int *sock){ 
cout<<"exiting"; 
close(*sock); 
exit(cond); 
} 

int main(void){ 
cout<<"working; 
int sock; 
int connect_sock; 
struct sockaddr_in serv_name; 
size_t len; 
int count; 

sock = socket(AF_INET, SOCK_STREAM, 0); 
if(sock<0){ 
cout<<"Error connecting to socket"; 
clean_up(1, &sock); 
} 
bzero(&serv_name, sizeof(serv_name)); // set name as physical address 
serv_name.sin_family = AF_INET; 
serv_name.sin_port = htons(PORT); 
if(bind(sock,(struct sockaddr *)&serv_name, sizeof(serv_name))<0){ 
cout<<"error naming channel"; 
clean_up(1, &sock); 
} 
cout<<"waiting for connection from client"; 
listen(sock, 1); 
len = sizeof(serv_name); 
connect_sock = accept(sock, (struct sockaddr *)&serv_name, &len); 
cout<<connect_sock; 
cout<<"server wrote"; 
close(connect_sock); 
cout<<"connect?"; 
} 

Answer 1

它正在等待連接。它不打印第一個cout，因爲你沒有要求。嘗試：

cout<<"waiting for connection from client"<<endl;