下面是一個程序,我很難用返回的double值輸出字符串消息。任何幫助非常感謝,我不知道從哪裏去。我可能過度思考它或看到一個簡單的解決方案。謝謝!難以輸出字符串與返回的雙重
預期輸出是:
average = 12.5
average = 7.63
average = 6.96
但是我的程序輸出:
12.5
7.63
6.96
這裏是我的代碼:
class Test2{
public static void main(String[] args){
int i, j;
double di, dj, dk;
i = 20;
j = 5;
Overload ol = new Overload();
System.out.println(ol.findAverage(i, j));
di = 14.29;
dj = 0.97;
System.out.println(ol.findAverage(di, dj));
di = 3.51;
dj = 13.5;
dk = 3.87;
System.out.println(ol.findAverage(di, dj, dk));
}
}
class Overload {
private int i, j;
private double di, dj, dk;
private double average;
public double findAverage(int i, int j) {
average = ((i + j)/2.0);
return average;
}
public double findAverage(double di, double dj) {
average = (di + dj)/2.0;
return average;
}
public double findAverage(double di, double dj, double dk) {
average = (di + dj + dk)/3.0;
return average;
}
public String findAverage() {
return "average = " + average;
}
}
嗨,你叫錯功能時你做你的輸出:你必須調用findAverage() – Tuco
作爲一個方面說明:閱讀有關可變參數https://www.javatpoint.com/varargs並寫一個方法來處理可變數量的參數:'findAverage(double ... d)' – c0der