我試圖加入兩個表。一個是類別,另一個是子類別。 ID在類別表成爲子類別表中的類別ID加入兩個表來顯示數據
類別
id name catimage
2 cat1 image1
子類別
id name subcatimage catid
1 subcat1 image2 2
代碼
<?php
ob_start();
require_once('config.php');
$selectsubcategory = mysql_query("SELECT category.name, subcategory.name, category.catimage, subcategory.id, subcategory.catid FROM category INNER JOIN subcategory ON category.id=subcategory.catid ");
$posts = array();
if(mysql_num_rows($selectsubcategory))
{
while($post = mysql_fetch_assoc($selectsubcategory))
{
$posts[] = $post;
}
header('Content-type: application/json');
echo stripslashes(json_encode(array('subcategorylist'=>$posts)));
}
else
{
header('Content-type: application/json');
echo stripslashes(json_encode(array('subcategorylist'=>'No subcategory')));
}
?>
我讓所有的細節,但問題是我沒有得到category.name結果。誰能幫助
P.S我已經使用SQL,稍後會馬上改變我關心的是部分功能
創建別名並檢查'「SELECT category.name as catname,subcategory.name as subcatname,category.catimage,subcategory.id,subcategory.catid FROM category INNER JOIN subcategory ON category.id = subcategory.catid」 – 2014-10-18 12:15:42