SQL IN子句更有效的方法

Question

我有這個sql查詢，這需要很長時間才能完成。我如何加快速度？

t_inter_specises_interaction有60k行，t_pathway有100k。 uniprot_id_1，uniprot_id_2，uniprot_id是varchar類型。

在該查詢中，我想選擇uniprot_id_1和uniprot_id_2其在t_pathway兩者都存在：

select distinct uniprot_id_1,uniprot_id_2 from t_intra_species_interaction 
where uniprot_id_1 in (select uniprot_id from t_pathway) and 
    uniprot_id_2 in (select uniprot_id from t_pathway) 

在這其中，我想選擇uniprot_id其存在於由所述第一查詢返回的集合uniprot_ids以上。

select distinct uniprot_id,id from t_pathway as t 
where uniprot_id in 
(
    select distinct uniprot_id_2 from t_intra_species_interaction 
    where uniprot_id_1 in (select uniprot_id from t_pathway) and 
     uniprot_id_2 in (select uniprot_id from t_pathway) 
    union 
    select distinct uniprot_id_1 from t_intra_species_interaction 
    where uniprot_id_1 in (select uniprot_id from t_pathway) and 
     uniprot_id_2 in (select uniprot_id from t_pathway) 
) 

謝謝。

Answer 1

的子查詢是相同的，因此它們可以被合併成一個，並移動到加入

SELECT DISTINCT i.uniprot_id_1, i.uniprot_id_2 
FROM t_intra_species_interaction i 
     INNER JOIN t_pathway p ON p.uniprot_id IN (i.uniprot_id_1, i.uniprot_id_2) 

第二個查詢
它必須是更好地打開一個新的問題，指的是這個，而是看我以前的查詢應該很容易地看到，讓你的第二個答案，你只需要得到從列t_pathway代替t_intra_species_interaction

SELECT DISTINCT p.uniprot_id, p.id 
FROM t_intra_species_interaction i 
     INNER JOIN t_pathway p ON p.uniprot_id IN (i.uniprot_id_1, i.uniprot_id_2) 

Answer 2

您可能需要使用INNER JOIN：

select distinct uniprot_id_1,uniprot_id_2 from t_intra_species_interaction i 
inner join t_pathway p1 
    on p1.uniprod_id = t.uniprot_id_1 
inner join t_pathway p2 
    on p2.uniprod_id = t_uniprot_id_2 

Answer 3

有一般guildline：

創建三個指標，一個在t_pathway.uniport_id，一個在t_intra_species_interaction.uniport_id1，另一個在t_intra_species_interaction.uniport_id2

通過這種所有你需要的數據都在你的索引中，並且它應該很快

另外c將你的子句反轉爲左連接Tomas在他的回答中提到了

Answer 4

EXISTS或JOIN會更有效率。

Answer 5

如何：

select distinct uniprot_id_1, uniprot_id_2 
from t_intra_species_interaction 
where exists (select uniprot_id from t_pathway 
       where uniprot_id_1 = uniprot_id) and 
     exists (select uniprot_id from t_pathway 
       where uniprot_id_2 = uniprot_id) 

Answer 6

試試這個：

select distinct uniprot_id_1,uniprot_id_2 
from t_intra_species_interaction I 
    join t_pathway P1 
    on I.uniprot_id_1 = P1.uniprot_id 
    join t_pathway P2 
    on I.uniprot_id_2 = P2.uniprot_id 

或

select distinct uniprot_id_1,uniprot_id_2 
from t_intra_species_interaction I 
where exists (select 1 from t_pathway where uniprot_id = I.uniprot_id_1) 
    and exists (select 1 from t_pathway where uniprot_id = I.uniprot_id_2)