添加PARAMS渲染方法

Question

我希望能夠「PARAMS」傳遞給「is_following」的方法如下：

 respond_to |format| 
      format.json { render json: @user, :methods => [:is_following params] } 
     end 

然而，當我把「PARAMS」方法名稱後，它會引發一個錯誤：

syntax error, unexpected tIDENTIFIER, expecting ']' 

。

。

當我呈現JSON（不is_following法），它看起來像這樣：

[{"id":81,"image_url":"https://graph.facebook.com/123213123/picture?type=large","full_name":"John Johnson"},{"id":85,"image_url":"https://graph.facebook.com/123123123/picture?type=large","full_name":"Bill Nye"}]

我想補充的is_following方法，以便JSON洛斯這樣的：

[{"id":81,"image_url":"https://graph.facebook.com/123213123/picture?type=large","full_name":"John Johnson",'is_following'=>4},{"id":85,"image_url":"https://graph.facebook.com/123123123/picture?type=large","full_name":"Bill Nye",'is_following'=>9}]

編輯

def friends 
    @user = User.first 
    respond_to do |format| 
    format.json { render json: @user.friends.order("first_name ASC"), :methods => [:is_following], :only => [:id] } 
    end 
end 

和is_following方法模式是：

def is_following params 
    return Friendship.where("user_id = ? AND friend_id = ?", params[:user_id], self.id).count 
end 

有誰知道如何解決這個問題？我會給你一百萬美元。

Answer 1

布賴恩，

只是更改此代碼：

:methods => [:is_following params] 

到

:is_following => is_following(params) 

編輯

這裏是一個更好的辦法無論如何要做到這一點：

def friends 
    @users = User.find_by_sql("SELECT users.*, 
     count(distinct friendships.friend_id) as is_following FROM users 
     LEFT JOIN friendships ON users.id = friendships.user_id 
     WHERE users.id = " + params[:user_id] + " 
     GROUP BY users.id 
     ORDER BY users.name ASC") 

    respond_to do |format| 
    format.json { render json: @users } 
    end 
end