爲什麼ThreadOne應該像你說的那樣工作? while循環從未運行,而是因爲條件不成立而被跳過。我認爲你期望它等待某些東西變爲真,但它沒有任何作用,而是一旦它發現某個條件是錯誤的,就結束執行。
注意,這是醜陋的代碼:
while(this.x.startApp != false) {
爲什麼狀態,而東西不假?這與爲真相同。 更好
while (x.startApp) {
現在爲您的實際問題,也許你應該反而讓你的while循環:
while (!x.startApp) {
Thread.sleep(1); // surrounded with try/catch
}
System.out.println("Starting");
例如,
class ThreadOne implements Runnable {
Thread t;
volatile MyVariables x;
public ThreadOne(MyVariables x) {
t = new Thread(this, "Thread One");
this.x = x;
}
@Override
public void run() {
while (!x.startApp) {
try {
Thread.sleep(1);
} catch (InterruptedException e) {
}
}
System.out.println("Starting");
}
public void start() {
t.start();
}
}
class ThreadTwo implements Runnable {
private static final int MAX_I = 10001;
Thread t;
volatile MyVariables x;
public ThreadTwo(MyVariables x) {
t = new Thread(this, "Thread One");
this.x = x;
}
@Override
public void run() {
synchronized (this.x) {
for (int i = 0; i <= MAX_I; i++) {
if (i == MAX_I) {
this.x.startApp = true;
System.out.println(this.x.startApp);
} else {
System.out.println(this.x.startApp);
System.out.println(i);
}
}
}
}
public void start() {
t.start();
}
}
public class StartThreads {
public static void main(String[] args) {
MyVariables a = new MyVariables();
ThreadOne x = new ThreadOne(a);
ThreadTwo y = new ThreadTwo(a);
x.start();
y.start();
}
}
class MyVariables {
public volatile boolean startApp = false;
}
另外,我認爲你的布爾字段應當至少是不穩定的。
使用一個PropertyChangeListener和觀察者模式的另一種方法:
import java.beans.PropertyChangeEvent;
import java.beans.PropertyChangeListener;
import java.beans.PropertyChangeSupport;
public class StartThreads2 {
public static void main(String[] args) {
final MyVariables2 myVars2 = new MyVariables2();
final RunOne runOne = new RunOne();
final RunTwo runTwo = new RunTwo(myVars2);
myVars2.addPropertyChangeListener(new PropertyChangeListener() {
@Override
public void propertyChange(PropertyChangeEvent pcEvt) {
if (MyVariables2.START_APP.equals(pcEvt.getPropertyName())) {
if (pcEvt.getNewValue().equals(Boolean.TRUE)) {
new Thread(runOne).start();
}
}
}
});
new Thread(runTwo).start();
}
}
class MyVariables2 {
public static final String START_APP = "start app";
private volatile boolean startApp = false;
private PropertyChangeSupport pcSupport = new PropertyChangeSupport(this);
public boolean isStartApp() {
return startApp;
}
public void setStartApp(boolean startApp) {
boolean oldValue = this.startApp;
boolean newValue = startApp;
this.startApp = startApp;
pcSupport.firePropertyChange(START_APP, oldValue, newValue);
}
public void addPropertyChangeListener(PropertyChangeListener listener) {
pcSupport.addPropertyChangeListener(listener);
}
public void removePropertyChangeListener(PropertyChangeListener listener) {
pcSupport.removePropertyChangeListener(listener);
}
}
class RunOne implements Runnable {
@Override
public void run() {
System.out.println("Starting RunOne");
}
}
class RunTwo implements Runnable {
private static final int MAX_I = 10001;
private MyVariables2 myVars2;
public RunTwo(MyVariables2 myVars2) {
this.myVars2 = myVars2;
}
@Override
public void run() {
for (int i = 0; i <= MAX_I; i++) {
System.out.println("startApp: " + myVars2.isStartApp());
System.out.printf("i: %05d%n", i);
}
myVars2.setStartApp(true);
try {
Thread.sleep(10);
} catch (InterruptedException e) {}
System.out.println("startApp: " + myVars2.isStartApp());
}
}
如果我改變而statment爲「如果(!this.x.startApp)」,它仍然沒有顯示,所以我不要不知道線程是否工作? –
@JohnArckai:查看最新編輯 –
while循環從不「退出」。它從未輸入時如何退出?它會在運行主體之前檢查條件,並且條件如您所說的那樣是假的,但它從不輸入,因此無法退出。我會理解這是否是一段時間。另外,如果你向他提到this.x.startApp需要在他的while循環運行時設置爲true,那最好。這是OP代碼唯一的錯誤。除此之外,在這種情況下沒有理由同步。 – Brandon