2017-08-11 51 views
2

我有一個小小的麻煩,因爲標題說:我無法弄清楚如何向槍指向的方向射擊子彈。Box2D - 從旋轉槍射擊子彈

Picture of problem

這裏是短版的代碼,我的子彈發射:

b2BodyDef bd; 
bd.type = b2_dynamicBody; 
bd.bullet = true; 
bd.position = gun->GetPosition();//bullet start at the middle of the gun 
m_bullet = m_world->CreateBody(&bd); 
m_bullet->CreateFixture(&fd);   
m_bullet->ApplyLinearImpulseToCenter(??? ,true); 

起初我還以爲第一個參數是你想要的身體去朝所以我把gun->GetWorldPoint(b2Vec2(0.0f,-5.0f))(中間的方向槍的槍口)。大錯過!過了一會兒,我想我應該嘗試把目前的槍的旋轉度b2Vec2 vect = b2Vec2(cos(angle * PI/180), sin(angle * PI/180));向量,但然後子彈將不會飛。現在我完全沒有想法。請點亮一下。

完整版的代碼:

public: 
b2Body* m_bullet = NULL; 
b2Body* gun; 
b2RevoluteJoint* joint1; 
b2FixtureDef fd; 

TestingStuff() 
{ 
    { 
     //body 
     b2CircleShape circle1; 
     circle1.m_radius = 1.6f; 

     fd.shape = &circle1; 
     fd.density = 1.0f; 
     fd.filter.groupIndex = -1;   

     b2BodyDef bd1; 
     bd1.type = b2_staticBody; 
     bd1.position.Set(-5.0f, 9.0f); 
     b2Body* body1 = m_world->CreateBody(&bd1); 
     body1->CreateFixture(&fd); 

     //gun 
     b2PolygonShape box; 
     box.SetAsBox(0.5f, 5.0f); 

     fd.shape = &box; 
     fd.density = 1.0f; 
     fd.filter.groupIndex = -1; 

     b2BodyDef bd2; 
     bd2.type = b2_dynamicBody; 
     bd2.position.Set(-5.0f, 8.0f); 
     gun = m_world->CreateBody(&bd2); 
     gun->CreateFixture(&fd); 

     //joint 
     b2RevoluteJointDef jd1; 
     jd1.Initialize(gun, body1, bd1.position); 
     jd1.enableMotor = true; 
     jd1.maxMotorTorque = 90; 
     jd1.motorSpeed = 180 * DEGTORAD;//DEGTORAD=0.0174532925199432957f 
     joint1 = (b2RevoluteJoint*) m_world->CreateJoint(&jd1); 
    } 

} 

void Keyboard(int key) 
{ 
    switch (key) 
    { 
    case GLFW_KEY_COMMA: 
     if (m_bullet != NULL) 
     { 
      m_world->DestroyBody(m_bullet); 
      m_bullet = NULL; 
     } 

     { 
      //bullet 
      b2CircleShape shape; 
      shape.m_radius = 0.25f; 

      fd.shape = &shape; 
      fd.density = 1; 
      fd.restitution = 0.05f; 
      fd.filter.groupIndex = -1; 

      b2BodyDef bd; 
      bd.type = b2_dynamicBody; 
      bd.bullet = true; 
      bd.position = gun->GetPosition(); 
      m_bullet = m_world->CreateBody(&bd); 
      m_bullet->CreateFixture(&fd); 
      m_bullet->ApplyLinearImpulseToCenter(??? ,true); 
     } 
     break; 
    } 
} 
+1

「'b2Vec2(cos(angle * PI/180),sin(angle))'」,是否是以弧度表示的角度? – genpfault

+0

@genpfault:對於90度,我會把角度= 90.0f – Dant

+0

我想我試圖指出,你沒有將'sin()'的參數轉換爲弧度,只有'cos()''秒。你需要做這兩件事,否則結果將是毫無意義的,或者至少是Funkytown的單程票。 – genpfault

回答

1

一個良好的睡眠後,我發現一些更多的試驗和錯誤後的溶液。

//bullet 
float degAngle = joint1->GetJointAngle() * RADTODEG + 180; 
b2Vec2 vect = b2Vec2(sin(degAngle* (b2_pi/180)) * 10, cos(degAngle* (b2_pi/180)) * 10); 
m_bullet->ApplyLinearImpulseToCenter(vect ,true); 

的* 10是增加的衝動,讓子彈飛得更快,更遠,用於測試的緣故,我只是使它10.注意這個代碼只是爲了測試,如果你想讓它更現實的是,增加衝動力,並使子彈朝向槍口而不是朝着它所射擊的媒介前進。