嗨，有人可以幫助我的這個循環

Question

對不起，這個問題，但我沒有其他地方去了，它讓我覺得我找不到解決方案。我對編程語言Pascal非常好，所以這個C語言對我來說似乎很熟悉，但添加一個if函數來改變while循環的整個結構對我來說太複雜了。請任何幫助表示讚賞。

The array variable consists of a sequence of ten numbers. Inside the while loop, you must write two if conditions, which change the flow of the loop in the following manner (without changing the printf command):

• If the current number which is about to be printed is less than 5, don't print it.
• If the current number which is about to be printed is greater than 10, don't print it and stop the loop.
  
  Notice that if you do not advance the iterator variable i and use the continue derivative, you will get stuck in an infinite loop.

#include <stdio.h> 

int main() 
{ 
    int array[] = {1, 7, 4, 5, 9, 3, 5, 11, 6, 3, 4}; 
    int i = 0; 

    while (i < 10) 
    { 
     /* your code goes here */ 

     printf("%d\n", array[i]); 
     i++; 
    } 
    return 0; 
} 

Answer 1

這是測試你對C流量控制的理解。你要找的東西是這樣的：

if (array[i] < 5) {i++; continue; } // increment, go back to while 
if (array[i] > 10) break;   // leave while 

Answer 2

你真的想用break和if語句。你需要知道這些概念是好與任何語言。

if (array[i] > 10) 
     break; 
if (array[i] >= 5) 
     printf("%d\n", array[i]);