PHP的preg_match聖經經文格式

Question

我與建立一個正則表達式解析這種字符串（聖經經文）掙扎：

'John 14:16–17, 25–26' 
    'John 14:16–17' 
    'John 14:16' 
    'John 14' 
    'John' 

所以基本模式是：

Book [[Chapter][:Verse]]

哪裏章節和詩節是可選的。

Answer 1

試試這個位置

\b[a-zA-Z]+(?:\s+\d+)?(?::\d+(?:–\d+)?(?:,\s*\d+(?:–\d+)?)*)? 

看到和測試here on Regexr

因爲(?:,\s*\d+(?:–\d+)?)*在年底可以有經文列表，經文範圍結尾。

Answer 2

使用這個表達式：

[A-Za-z]+(([0-9]+)(:[0-9]+)?([\-–][0-9]+)?(, [0-9]+[\-–][0-9]+)?)? 

或者在它的 '漂亮' 的版本：

\w+((\d+)(:\d+)?([\-–]\d+)?(, \d+[\-–]\d+)?)? 

---

更新：要匹配破折號或連字符

---

NOTE：我測試過它，它匹配所有5個可能的版本。

例子：http://regexr.com?30h4q

Answer 3

我認爲這確實你需要：

\w+\s?(\d{1,2})?(:\d{1,2})?([-–]\d{1,2})?(,\s\d{1,2}[-–]\d{1,2})? 

假設：

• 的數字總是在套1或2位數字
• 破折號將匹配以下-和–

下面是正則表達式與評論：

" 
\w   # Match a single character that is a 「word character」 (letters, digits, and underscores) 
    +   # Between one and unlimited times, as many times as possible, giving back as needed (greedy) 
\s   # Match a single character that is a 「whitespace character」 (spaces, tabs, and line breaks) 
    ?   # Between zero and one times, as many times as possible, giving back as needed (greedy) 
(   # Match the regular expression below and capture its match into backreference number 1 
    \d   # Match a single digit 0..9 
     {1,2}  # Between one and 2 times, as many times as possible, giving back as needed (greedy) 
)?   # Between zero and one times, as many times as possible, giving back as needed (greedy) 
(   # Match the regular expression below and capture its match into backreference number 2 
    :   # Match the character 「:」 literally 
    \d   # Match a single digit 0..9 
     {1,2}  # Between one and 2 times, as many times as possible, giving back as needed (greedy) 
)?   # Between zero and one times, as many times as possible, giving back as needed (greedy) 
(   # Match the regular expression below and capture its match into backreference number 3 
    [-–]  # Match a single character present in the list 「-–」 
    \d   # Match a single digit 0..9 
     {1,2}  # Between one and 2 times, as many times as possible, giving back as needed (greedy) 
)?   # Between zero and one times, as many times as possible, giving back as needed (greedy) 
(   # Match the regular expression below and capture its match into backreference number 4 
    ,   # Match the character 「,」 literally 
    \s   # Match a single character that is a 「whitespace character」 (spaces, tabs, and line breaks) 
    \d   # Match a single digit 0..9 
     {1,2}  # Between one and 2 times, as many times as possible, giving back as needed (greedy) 
    [-–]  # Match a single character present in the list 「-–」 
    \d   # Match a single digit 0..9 
     {1,2}  # Between one and 2 times, as many times as possible, giving back as needed (greedy) 
)?   # Between zero and one times, as many times as possible, giving back as needed (greedy) 
" 

這裏是在PHP中的一些用法示例：

if (preg_match('/\w+\s?(\d{1,2})?(:\d{1,2})?([-–]\d{1,2})?(,\s\d{1,2}[-–]\d{1,2})?/', $subject)) { 
    # Successful match 
} else { 
    # Match attempt failed 
} 

獲取給定字符串中所有匹配的數組

preg_match_all('/\w+\s?(\d{1,2})?(:\d{1,2})?([-–]\d{1,2})?(,\s\d{1,2}[-–]\d{1,2})?/', $subject, $result, PREG_PATTERN_ORDER); 
$result = $result[0]; 

Answer 4

([1|2|3]?([i|I]+)?(\s?)\w+(\s+?))((\d+)?(,?)(\s?)(\d+))+(:?)((\d+)?([\-–]\d+)?(,(\s?)\d+[\-–]\d+)?)? 

適用於幾乎每本書...

Answer 5

(\b[a-zA-Z]\w+\s\d+)(:\d+)+([-–]\d+)?([,;](\s)?(\d+:)?\d+([-–]\d+)?)? 

這是這裏介紹的所有代碼的混合。唯一的格式，它不會強調是「書名只」或「書&節只」（剛加入「：1，所有」後章＃）我發現提供給有資格太多變化的其他代碼，不符合聖經經文的語法。

這些是我在RegExr測試的例子：（不能發表圖片尚未）

約翰 洪堡14：16-17，25-26
約14： 16-17
約翰14:16
約翰77：3; 2：9-11
約5：1-所有 布拉德555-783-6867
約翰6
您好你怎麼樣
斯拉32：5約14 ：16-17，25-36
23時34分
約14：16-17,25-36
約翰福音14：16-17; 32:25