獲取行項目的子集的排列在SQLSERVER表中所有行

Question

說我有這樣的一個表：

idx | a1 | a2 | a3 | b1 | c1 
----------------------------- 
idx1, a11, a12, a13, b11, c11 
idx2, a21, a22, a23, b21, c21 
idx3, a31, a32, a33, b31, c31 
idx4, a41, a42, a43, b41, c41 

，我想行添加到具有列子集的置換表（ a1，a2，a3）。例如。 row1會貢獻額外的行，如：

idx | a1 | a2 | a3 | b1 | c1 
----------------------------- 
idx1, a11, a12, a13, b11, c11 
idx1, a11, a13, a12, b11, c11 
idx1, a12, a11, a13, b11, c11 
idx1, a12, a13, a11, b11, c11 
idx1, a13, a11, a12, b11, c11 
idx1, a13, a12, a11, b11, c11 
and so on for the other original rows... 

是我將如何做到這一點在sqlserver？

謝謝:)

Answer 1

這是一個交叉連接方法。

declare @table table (indx varchar(4), a1 varchar(3), a2 varchar(3), a3 varchar(3), b1 varchar(3), c1 varchar(3)) 
insert into @table 
values 
('idx1','a11','a12','a13','b11','c11'), 
('idx2','a21','a22','a23','b21','c21') 

;with cte as(
    select indx, a1 
    from @table 
    union 
    select indx, a2 
    from @table 
    union 
    select indx, a3 
    from @table) 

select distinct 
    c1.indx 
    ,c1.a1 
    ,c2.a1 as a2 
    ,c3.a1 as a3 
    ,t.b1 
    ,t.c1 
from cte c1 
    cross join cte c2 
    cross join cte c3 
    left join @table t on t.indx = c1.indx 
where 
    c1.indx = c2.indx 
    and c3.indx = c1.indx 
    and c1.a1 <> c2.a1 
    and c1.a1 <> c3.a1 
    and c2.a1 <> c3.a1 
order by 
    c1.indx 
    ,c1.a1 
    ,c2.a1 
    ,c3.a1 

退貨

+------+-----+-----+-----+-----+-----+ 
| indx | a1 | a2 | a3 | b1 | c1 | 
+------+-----+-----+-----+-----+-----+ 
| idx1 | a11 | a12 | a13 | b11 | c11 | 
| idx1 | a11 | a13 | a12 | b11 | c11 | 
| idx1 | a12 | a11 | a13 | b11 | c11 | 
| idx1 | a12 | a13 | a11 | b11 | c11 | 
| idx1 | a13 | a11 | a12 | b11 | c11 | 
| idx1 | a13 | a12 | a11 | b11 | c11 | 
| idx2 | a21 | a22 | a23 | b21 | c21 | 
| idx2 | a21 | a23 | a22 | b21 | c21 | 
| idx2 | a22 | a21 | a23 | b21 | c21 | 
| idx2 | a22 | a23 | a21 | b21 | c21 | 
| idx2 | a23 | a21 | a22 | b21 | c21 | 
| idx2 | a23 | a22 | a21 | b21 | c21 | 
+------+-----+-----+-----+-----+-----+ 

Answer 2

你試過類似下面的東西嗎？您的問題對於a1，a2，a3列的唯一性和內容非常模糊。

WITH cte AS (
    SELECT Idx, b1, c1, a1 AS a 
    UNION 
    SELECT Idx, b1, c1, a2 AS a 
    UNION 
    SELECT Idx, b1, c1, a3 AS a 
) 
SELECT cte1.Idx, cte1.b1, cte1.c1, cte1.a AS a1, cte2.a AS a2, cte3.a AS a3 
FROM cte AS cte1 
    JOIN cte AS cte2 ON cte1.Idx = cte2.Idx AND cte1.b1 = cte2.b1 AND cte1.c1 = cte2.c1 
    JOIN cte AS cte3 ON cte1.Idx = cte3.Idx AND cte1.b1 = cte3.b1 AND cte1.c1 = cte3.c1 

Answer 3

置換，5！提供每個idx的組合，提供源行中的所有值都是不同的。

declare @t table(
    idx varchar(10) 
    , a1 varchar(10) 
    , a2 varchar(10) 
    , a3 varchar(10) 
    , b1 varchar(10) 
    , c1 varchar(10) 
    ); 
insert @t 
values 
('idx1','a11','a12','a13','b11','c11') 
,('idx2','a21','a22','a23','b21','c21') 
,('idx3','a31','a32','a33','b31','c31') 
,('idx4','a41','a42','a43','b41','c41'); 

with pvt as (
    select idx,m 
    from @t 
    cross apply ( 
     values(a1),(a2),(a3),(b1),(c1) 
     ) vals(m) 
) 

select t1.idx, t1.m, t2.m, t3.m, t4.m, t5.m 
from pvt t1 
join pvt t2 on t1.idx=t2.idx and t2.m not in (t1.m) 
join pvt t3 on t1.idx=t3.idx and t3.m not in (t1.m, t2.m) 
join pvt t4 on t1.idx=t4.idx and t4.m not in (t1.m, t2.m, t3.m) 
join pvt t5 on t1.idx=t5.idx and t5.m not in (t1.m, t2.m, t3.m, t4.m) 
order by t1.idx, t1.m, t2.m, t3.m, t4.m, t5.m;