SQL SELECT語句同時獲得一個值的總

Question

您好我有以下的select語句

 select 
     a.amount 
     ,b.des 
     ,a.id 
     ,SUM(a.amount) as total 
     ,b.id 
     from t_sales a 
     left outer join t_location b on(b.id=a.orgId) 
     where a.Id=@salesId and 
     a.sId=@supId 
     GROUP BY a.amount, b.des, a.Id,b.id; 

一切工作正常，但總。我正在嘗試獲得返回15個值的a.amount的總數，所以我希望總共有15個值。請讓我知道如何解決它。 感謝

Answer 1

您應該刪除從選擇列表a.amount柱（聚合列不應該在選擇列表中存在）

select b.des, a.id, a.amount ,SUM(a.amount) over(partition by 1) as total, b.id from t_sales a left outer join t_location b on(b.id=a.orgId) 
    where a.Id=@salesId and a.sId=@supId GROUP BY b.des, a.Id, b.id; 

Answer 2

你可以嘗試

select   a.amount, b.des, a.id, b.id, 
        (select   sum(a.amount) 
        from    t_sales a 
        left outer join t_location b on (b.id = a.orgId) 
        where    a.Id = @salesId 
        and    a.sId = @supId 
        GROUP BY   b.des, a.Id, b.id) as total 
from    t_sales a 
left outer join t_location b on (b.id = a.orgId) 
where    a.Id = @salesId 
and    a.sId = @supId 
GROUP BY   a.amount, b.des, a.Id, b.id; 

Answer 3

請嘗試：

select 
    a.amount 
    ,b.des 
    ,a.id 
    ,SUM(a.amount) over(partition by 1) as total 
    ,b.id 
from t_sales a 
    left outer join t_location b on(b.id=a.orgId) 
where 
    a.Id=@salesId and 
    a.sId=@supId;