如何在一個表中顯示兩個查詢的結果

我的select查詢，我已經刪除t0.brandID = null它並不重要，只需要在一個表中獲取查詢結果。如何在一個表中顯示兩個查詢的結果

SELECT 
    t0.brandID, t0.brandName, t0.cdt, t0.udt, t0.brandstatus, t0.AddedBy 
FROM 
    brands t0 
WHERE 
    t0.brandName = 'budwieser' 

SELECT 
    AVG(CAST (brandID AS bigint)) AS brandID_AVERAGE, 
    MIN(CAST (brandID AS bigint)) as branid_min, 
    MAX(CAST (brandID AS bigint)) as brandid_max, 
    COUNT(CAST (brandID AS bigint)) as brandid_count 
FROM 
    (SELECT 
     t0.brandID, t0.brandName, t0.cdt, t0.udt, t0.brandstatus, t0.AddedBy 
    FROM 
     brands t0 
    WHERE 
     t0.brandID = null OR t0.brandName = 'budwieser') temptable

上述查詢的結果是在兩個不同的表，如下圖：

brandid brandname  cdt      udt  brandstatus added by 

    8 budwieser 2013-11-14 16:26:43.913 2014-02-12 19:26:43.913 1 8 
    18 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 
    23 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 
    37 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 
    63 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 
    82 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 
    92 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1

和

我想顯示如下結果：

brandid brandname cdt    udt brandstatus addedby branid_average brandid_min brandid_max branid_count 
    8 budwieser 2013-11-14  2014-02-12 1 8   46    8    92    7 
    18 budwieser 2013-11-15  2013-11-15 1 1   null   null   null   null 
    ........................................................  null   null   null   null 
    --------------------------------------------------------  null   null   null   null

來源

2016-03-21 Tan

您不能使用常規的相等運算符檢查'NULL' - 你需要使用'to.BrandID IS NULL'（使用' IS NULL'或'IS NOT NULL' - 不是'= null'）。 –

你能解釋爲什麼你的預期產量有8個百威啤酒記錄的計算值，而不是18個百威啤酒記錄？閱讀你的問題，我期待在百威啤酒的所有記錄中都有相同的價值觀。你如何關聯/配對2個查詢的結果？ –

謝謝，我必須計算選定記錄的平均值，最小值，最大值。在我的表格中，我在Branid's（8,18,23，...，92）有budwiser條目，平均值爲（8 + 18 + 23 + ..）/ 7 = 46.07，接近46.選定記錄的最小brandid是8，所選記錄的最大brandid是92，記錄數是7.我必須顯示這些值以及選定的值，如branid，brandname，..，brandid_average，branid_min，brandid_max，brandid_count。這是測試場景，實際使用將用於計算不同逆變器的電壓。這將作爲報告導出爲excel。 – Tan

在這種情況下，兩個表結果需要結合起來，可以通過從兩個表中選擇來簡單完成。例如table1，table2。

Table1 has columns id,name,age 
table2 has columns someid,group,gender

的結果顯示如下格式簡單的查詢是：

select t1.*,t2.* from table1 t1,table2 t2 

id name age someid group gender 
1 one 1 10  5  M

同樣，對於上述問題，因爲沒有物理表存在，我們要聲明一個表，並保存值到臨時表，然後簡單地從兩個表中選擇將返回問題所需的結果。

 drop table #mytemptable --- droping the temporary table if exists 
//select query 
     select AVG(CAST (brandID AS bigint)) AS brandID_AVERAGE, 
     min(CAST (brandID AS bigint)) as branid_min, 
     MAX(CAST (brandID AS bigint)) as brandid_max, 
     COUNT(CAST (brandID AS bigint)) as brandid_count 
into #mytemptable ---//Here inserting the selected values from below query to temporary table 
    from 
     (SELECT t0.brandID, t0.brandName, t0.cdt, t0.udt, t0.brandstatus, t0.AddedBy 

     FROM brands t0 
     Where t0. brandID=null OR t0. brandName='budwieser' 

     ) temptable 
     //simple select from both tables 
     SELECT t0.brandID, t0.brandName, t0.cdt, t0.udt, t0.brandstatus, t0.AddedBy ,t2.* 
     from brands t0,#mytemptable t2 
     where t0.brandName='budwieser'

預期的結果將是：

brandID brandName cdt udt brandstatus AddedBy brandID_AVERAGE branid_min brandid_max brandid_count 
8 budwieser 2013-11-14 16:26:43.913 2014-02-12 19:26:43.913 1 8 46 8 92 7 
18 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 
23 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 
37 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 
63 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 
82 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7 
92 budwieser 2013-11-15 19:14:18.123 2013-11-15 19:14:18.123 1 1 46 8 92 7

來源

2016-03-21 17:29:49 Tan

SELECT t0.brandID, 
     t0.brandName, 
     t0.cdt, 
     t0.udt, 
     t0.brandstatus, 
     t0.AddedBy, 
     AVG(CAST(brandID AS BIGINT)) OVER(PARTITION BY t0.brandName) AS brandID_AVERAGE, 
     MIN(CAST(brandID AS BIGINT)) OVER(PARTITION BY t0.brandName) AS branid_min, 
     MAX(CAST(brandID AS BIGINT)) OVER(PARTITION BY t0.brandName) AS brandid_max, 
     COUNT(CAST(brandID AS BIGINT)) OVER(PARTITION BY t0.brandName) AS brandid_count 
FROM brands t0 
WHERE t0.brandName = 'budwieser'

來源

2016-03-21 17:58:03

如果我選擇兩個日期而不是「Where t0.brandname ='budwieser'」to「where t0.cdt> ='2013-11-14'and t0.cdt <='2013-11-15'」它會將brandid_average始終作爲brandid，brandid_min作爲brandid，brandid_max作爲brandid，brandid_count將始終爲1，這是不正確的。如果你檢查我上面提供的答案，你將where子句更改爲任何你會得到完美結果的平均值，最小值，最大值和數值......這僅僅是爲了您的信息，希望您同意，如果我錯了，請糾正我 – Tan

如何在一個表中顯示兩個查詢的結果

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