我想用awk刪除某些行開頭的字符。我想刪除的字符是@和/或=使用awk刪除某行開頭的某些字符
下面是一個文件的例子：
@word <= Remove @
=word <= Remove =
@=word <= Remove @ AND =
[email protected] <= Remove = AND @
目前，我用sub(/^\@/, "", $0)在一行的開頭刪除@。我如何編輯這一行，以便刪除@，=以及兩者是否一起存在？
在awk中：
$ awk 'gsub(/^[[email protected]]+/,"")||1' file
word <= Remove @
word <= Remove =
word <= Remove @ AND =
word <= Remove = AND @
解釋：
awk '
gsub(/^[[email protected]]+/,"") || 1 # replace all leading =s and @s with "" and print nevertheless
' file
隨着awk：
awk '{sub(/^[@=]+/, "")}1' File
隨着sed：
sed -r 's/^[@=]+//' File