向下舍入sql server 2008 r2

Question

對於員工11來說，任何想法都會降低總員工的薪水10.44，但是對於某些重新設置，其舍入爲10，即使他們都設置爲小數（8,2）

ALTER procedure [dbo].[hms_GetEmployeeSallaryByEmpNo] 
    (

    @Id int 
    ) 
as 
/* lets make our tempory tables */ 
create table #contracts 
( 
empno INT, 
contract_id INT 
) 

DECLARE @contract_id int 
DECLARE @totalsallary decimal(8,2) 
begin 
    INSERT into #contracts SELECT c.emp_no,c.contract_id 
    FROM contract c 
    where c.emp_no = @Id AND c.leave_date='1900-01-01 00:00:00.000' 
end 

SET @totalsallary =(select SUM(salary) 
from #contracts c,salary s 
where s.contract_id = c.contract_id) 
return @totalsallary 

Answer 1

存儲過程只能返回整數值：

從MSDN：

存儲過程可以返回一個在對於調用程序或應用程序來說，泰格的價值。

你需要的是一個輸出參數：

ALTER procedure [dbo].[hms_GetEmployeeSalaryByEmpNo] 
(
    @Id int, 
    @totalsalary decimal(8,2) OUTPUT 
) 
... 
SET @totalsalary = 
(
    SELECT SUM(salary) 
    FROM #contracts c,salary s 
    WHERE s.contract_id = c.contract_id 
) 

--return @totalsalary -- not necessary anymore 

或標量值功能：

CREATE FUNCTION [dbo].[hms_GetEmployeeSalaryByEmpNo] 
(
    @Id int 
) 
RETURNS DECIMAL(8,2) 
AS 
.... 
SET @totalsalary = 
(
    SELECT SUM(salary) 
    FROM #contracts c,salary s 
    WHERE s.contract_id = c.contract_id 
) 

RETURN @totalsalary 

*也注意到，我在糾正 「工資」 的拼寫我的例子。