下面是評論我的想法:
// stacked contours
int main(int argc, char* argv[])
{
cv::Mat input = cv::imread("C:/StackOverflow/Input/Contours_in_Contours.png");
cv::Mat input_red = cv::imread("C:/StackOverflow/Input/Contours_in_Contours_RED.png");
cv::Mat reds;
cv::inRange(input_red, cv::Scalar(0, 0, 200), cv::Scalar(50, 50, 255), reds);
std::vector<std::vector<cv::Point> > contours1;
cv::findContours(reds, contours1, CV_RETR_EXTERNAL, CV_CHAIN_APPROX_NONE);
cv::Mat input_yellow = cv::imread("C:/StackOverflow/Input/Contours_in_Contours_YELLOW.png");
cv::Mat yellows;
cv::inRange(input, cv::Scalar(0, 200, 200), cv::Scalar(0, 255, 255), yellows);
std::vector<std::vector<cv::Point> > contours2;
cv::findContours(yellows, contours2, CV_RETR_EXTERNAL, CV_CHAIN_APPROX_NONE);
// now we have 2 sets of contours and want to find out whether contours of set2 are completely within a contour of contours1 without hierarchy information.
std::vector<cv::Mat> masks1;
std::vector<int> nMaskPixels1;
// for each contour in contours1: create a contour mask:
for (int i = 0; i < contours1.size(); ++i)
{
cv::Mat mask1 = cv::Mat::zeros(input.size(), CV_8UC1);
cv::drawContours(mask1, contours1, i, cv::Scalar::all(255), -1); // draw filled
int nPixel1 = cv::countNonZero(mask1);
masks1.push_back(mask1);
nMaskPixels1.push_back(nPixel1);
}
std::vector<cv::Mat> masks2;
std::vector<int> nMaskPixels2;
// for each contour in contours2: test whether it is completely within the reference contour:
for (int j = 0; j < contours2.size(); ++j)
{
cv::Mat mask2 = cv::Mat::zeros(input.size(), CV_8UC1);
cv::drawContours(mask2, contours2, j, cv::Scalar::all(255), -1); // draw filled
int nPixel2 = cv::countNonZero(mask2);
masks2.push_back(mask2);
nMaskPixels2.push_back(nPixel2);
}
for (int i = 0; i < masks1.size(); ++i)
{
cv::Mat mask1 = masks1[i];
// draw mask again for visualization:
cv::Mat outIm = input.clone();
cv::drawContours(outIm, contours1, i, cv::Scalar(0, 0, 0), 3);
for (int j = 0; j < masks2.size(); ++j)
{
cv::Mat mask2 = masks2[j];
cv::Mat overlap = mask1 & mask2;
int nOverlapPixels = cv::countNonZero(overlap);
if (nOverlapPixels == 0) continue; // no overlap at all. Test next contour.
if (nOverlapPixels == nMaskPixels2[j] && nOverlapPixels < nMaskPixels1[i])
{
// second contour is completely within first contour
cv::drawContours(outIm, contours2, j, cv::Scalar(0, 255, 0), 3);
}
else if (nOverlapPixels == nMaskPixels2[j] && nOverlapPixels == nMaskPixels1[i])
{
// both contours are identical
std::cout << "WARNING: " << "contours " << i << " and " << j << " are identical" << std::endl;
}
else if (nOverlapPixels < nMaskPixels2[j] && nOverlapPixels == nMaskPixels1[i])
{
// first contour is completely within second contour
std::cout << "WARNING: " << "contour " << i << " of the first set is inside of " << j << std::endl;
}
else if (nOverlapPixels < nMaskPixels2[j] && nOverlapPixels < nMaskPixels1[i])
{
// both contours intersect
cv::drawContours(outIm, contours2, j, cv::Scalar(255, 0, 255), 3);
}
}
cv::imshow("contours", outIm);
cv::imwrite("C:/StackOverflow/Output/contours.png", outIm);
cv::waitKey(0);
}
cv::imshow("input", input);
cv::waitKey(0);
return 0;
}
此代碼將從這兩個圖像創建兩套輪廓:
計算輪廓口罩和比較他們。
結果將按每個輪廓顯示。黑色輪廓是參考,綠色是完全在參考內的那些,紫色是相交的輪廓。
我使用這個圖像上繪製的結果:
得到這些結果:
contour1:
輪廓2:
contour3:
contour4:
contour5:
正如你所看到的,孤獨的黃色輪廓未檢測到相交或包含在任何的那些紅色輪廓。
爲什麼你不能使用輪廓層次結構?你能將所有的輪廓複製到一個單一的圖像,並再次提取它們嗎? – tfv
@tfv謝謝!但是,我必須爲我的應用程序保留兩組輪廓線。 – Vin
對於每個輪廓:在黑色圖像(作爲蒙版)上繪製它,然後爲每個輪廓蒙板:if mask1 && mask2 == mask2然後mask2完全位於掩碼1。也許不是最快的方法,但它應該工作。 – Micka