C++ pthreads - 嘗試鎖定互斥讀取時崩潰

類LocalT擁有其他類的成員，它們實現了read-write-mutex。互斥體在構造函數初始化並使用pthread_rwlock_rdlock(&aMutex);進行讀取鎖定。所以，看來，它與互斥類完全一樣。但是當一些對象鎖定他的互斥成員閱讀時，程序崩潰了。C++ pthreads - 嘗試鎖定互斥讀取時崩潰

CSerialize.cpp:2054線MUTEX.lock_reading();

Thread 6 (Thread 0x80d4e00 (runnable)): 
#0 0x4864f11d in pthread_mutex_lock() from /lib/libpthread.so.2 
#1 0x4864b558 in pthread_rwlock_init() from /lib/libpthread.so.2 
#2 0x4864b659 in pthread_rwlock_rdlock() from /lib/libpthread.so.2 
#3 0x0807ae14 in LocalT::serialize (this=0x80d4e00, [email protected]) 
    at CSerialize.cpp:2054

另外兩個正在運行的線程：

1）插座accept();

2）未來運行的線程在popen()電話，似乎其執行或管read。但不知道什麼是__error() ?????

Thread 1 (Thread 0x8614800 (LWP 100343)): 
#0 0x4865b8f9 in __error() from /lib/libpthread.so.2 
#1 0x4865a15a in pthread_testcancel() from /lib/libpthread.so.2 
#2 0x486425bf in read() from /lib/libpthread.so.2 
#3 0x08056340 in UT::execute_popen ([email protected], 
    ptr_output=0xbf2f7d30) at Utils.cpp:75

3）所有其他線程正在睡覺。

我不知道它爲什麼墜毀？也許有人可以承擔一些事情或建議？

== ==編輯

，這裏是一個系統（？）線程（我不會創建它，但計劃總是有+1線程）。它總是：

Thread 8 (Thread 0x80d4a00 (LWP 100051)): 
#0 0x4865a79b in pthread_testcancel() from /lib/libpthread.so.2 
#1 0x48652412 in pthread_mutexattr_init() from /lib/libpthread.so.2 
#2 0x489fd450 in ??()

== EDIT2 - BT的要求==

(gdb) bt 
#0 0x4865a7db in pthread_testcancel() from /lib/libpthread.so.2 
#1 0x48652412 in pthread_mutexattr_init() from /lib/libpthread.so.2 
#2 0x489fd450 in ??()

奇怪......爲什麼??()？

== EDIT3 - 裝載芯==

Program terminated with signal 11, Segmentation fault. 
[skiped] 
#0 0x4865a7db in pthread_testcancel() from /lib/libpthread.so.2 
[New Thread 0x8614800 (LWP 100343)] 
[New Thread 0x8614600 (sleeping)] 
[New Thread 0x8614400 (sleeping)] 
[New Thread 0x8614200 (sleeping)] 
[New Thread 0x8614000 (sleeping)] 
[New Thread 0x80d4e00 (runnable)] 
[New Thread 0x80d4c00 (sleeping)] 
[New Thread 0x80d4a00 (LWP 100051)] 
[New Thread 0x80d4000 (runnable)] 
[New LWP 100802] 

(gdb) info thread 
* 10 LWP 100802 0x4865a7db in pthread_testcancel() from /lib/libpthread.so.2 
    9 Thread 0x80d4000 (runnable) 0x486d7bd3 in accept() from /lib/libc.so.6 -- MAIN() THREAD 
    8 Thread 0x80d4a00 (LWP 100051) 0x4865a79b in pthread_testcancel() 
    from /lib/libpthread.so.2 (UNIDENTIFIED THREAD system()?) 
    7 Thread 0x80d4c00 (sleeping) 0x48651cb6 in pthread_mutexattr_init() 
    from /lib/libpthread.so.2 (SIGNAL PROCESSOR THREAD) 
    6 Thread 0x80d4e00 (runnable) 0x4864f11d in pthread_mutex_lock() 
    from /lib/libpthread.so.2 (MAINTENANCE THREAD) 
    5 Thread 0x8614000 (sleeping) 0x48651cb6 in pthread_mutexattr_init() 
    from /lib/libpthread.so.2 (other mutex cond_wait - worker 1) 
    4 Thread 0x8614200 (sleeping) 0x48651cb6 in pthread_mutexattr_init() 
    from /lib/libpthread.so.2 (other mutex cond_wait - worker 2) 
    3 Thread 0x8614400 (sleeping) 0x48651cb6 in pthread_mutexattr_init() 
    from /lib/libpthread.so.2 (other mutex cond_wait - worker 3) 
    2 Thread 0x8614600 (sleeping) 0x48651cb6 in pthread_mutexattr_init() 
    from /lib/libpthread.so.2 (other mutex cond_wait - worker 4) 
    1 Thread 0x8614800 (LWP 100343) 0x4865b8f9 in __error() 
    from /lib/libpthread.so.2 (popen() thread see below)

當我創建：1個維護線程（串行化），1個popen()螺紋，4名工人，1個主，1條信號線= 8個線程.. ..

來源

2012-06-14 abrahab

您提到的系統線程的線程實際上是您的程序的main thread。其次，由於你迄今共享的信息，它看起來像你正在獲取互斥鎖，但從未釋放它。導致一個不穩定的狀態（一些參數有錯誤的值），導致崩潰。我相信你也會觀察到間歇性的掛斷。

可以在碰撞時分享backtrace嗎？

來源

2012-06-14 23:10:01

感謝您的回答。 1）否，主線程處於'accept（）'狀態。也許它在sigwait（）狀態下的信號線程2）我將嘗試搜索我使用這個互斥鎖的代碼，但是......似乎不是，我總是注意這個...... 3）增加了一些額外的信息。 – abrahab

請''線程'，這將顯示你所有的線程 –

如果我上面提到關於不放棄鎖是真的，你會看到一堆線程在等待那個互斥量 –

C++ pthreads - 嘗試鎖定互斥讀取時崩潰

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