在while循環中提交按鈕

對於有經驗的用戶，我的問題可能很容易，但是我對此感到困惑。所以，這是問題。我在while循環中提交了按鈕，但是它們不會對點擊作出反應。這是我的一段代碼。在while循環中提交按鈕

`<?php 
$zap_cmember = count_query("SELECT * FROM `users` WHERE `clan` = '".$member['id']."' AND clan_stat != 'Призывник'"); 
while ($cmember = mysql_fetch_array($zap_cmember)) 
{ 
$zap_gold = mysql_result(mysql_query("SELECT SUM(gold) FROM klog WHERE name = '".$cmember['name']."'"), 0); 
$zap_online = mysql_num_rows(count_query("SELECT * FROM `online` WHERE `id_session`='".$cmember['id_user']."'")); 
if ($zap_online > 0) 
{ 
    $img_on = "<td align='center' valign='middle' ><img src='images/ico_online.png' alt='онлайн' class='png' ></td>"; 
} 
else 
{ 
    $img_on = "<td align='center' valign='middle' ><img src='images/ico_offline.png' alt='оффлайн' class='png' ></td>"; 
} 
$i = 'set'; 
echo '<tr> 
     <td width="141" height="25" align="left" valign="middle" ><a href="player.php?id='.$cmember['id_user'].'" class="text_main_5">'.$cmember['name'].' ['.lvl($cmember['exp']).']</a></td> 
     <td align="center" valign="middle" ><span class="text_main_4">'.$cmember['clan_stat'].'</span></td> 
     <td align="center" valign="middle" ><span class="text_main_4">-</span></td> 
     <td align="center" valign="middle" ><span class="text_main_4">'.$zap_gold.'</span></td> 
     <td align="center" valign="middle" ><span class="text_main_4">'.$cmember['glory'].'</span></td> 
     '.$img_on.''; 
     if($boss) 
     {echo '<td align="center" id = "'.$i.'" valign="middle"><input type="submit" name="bSet" value="Назначить"></span></td>'; } 
     $i++; 
     $player = $cmember; 
    '</tr>'; 

    if (isset($_POST['bSet'])) 
    { 
    echo 'works'; 
    count_query("UPDATE users SET clan_stat='Вождь' WHERE id_user='".$player['id_user']."'"); 
    $time = date('j.n.y H:i'); 
    count_query("INSERT INTO `message` (`time`, `to`, `text`, `metka`) VALUES ('".$time."', '".$player['name']."', 'Вас выбрали главой клана <a href=clan.php>".$clan['name']."</a>', '6')"); 
    echo "<script>location.href='clan.php'</script>"; 
    } 
} 
?>

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2016-03-29 Denis Kushnirenko

這段代碼在'form'元素裏面是嗎？如果輸入類型不在表單中，則不會提交輸入類型提交... – Stuart

你需要把要submit到<form id="yid">... </form>的一切，之後把上的按鈕的onclick="javascript:$('#yid').submit()"和YID =你想要的形式的特定ID按鈕提交。

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2016-03-30 05:23:23

在while循環中提交按鈕

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