在MySQL的一個表上使用兩個連接？

Question

由於添加查詢的中間部分（INNER JOIN），查詢現在失敗。我認爲這可能是因爲我在一個表上有兩種類型的連接（charts_extended） - 我看不到從dj_love表獲取所需數據的另一種方式。

SELECT DISTINCT releases . * 
FROM releases 
INNER JOIN artist_love ON releases.all_artists LIKE CONCAT('%', artist_love.artist, '%') 
AND artist_love.user = 'Quickinho' 
INNER JOIN label_love ON releases.label_no_country = label_love.label 
AND label_love.user = 'Quickinho' 

INNER JOIN charts_extended ON charts_extended.release_id = releases.id 
WHERE charts_extended.artist 
IN (

    SELECT dj 
    FROM dj_love 
    WHERE user = 'Quickinho' 
    ) 

LEFT JOIN charts_extended ON charts_extended.release_id = releases.id 
AND charts_extended.artist = 'Quickinho' 
WHERE charts_extended.release_id IS NULL 

ORDER BY releases.date DESC 

Answer 1

試試這個：

SELECT DISTINCT releases . * 
FROM releases 
INNER JOIN artist_love 
    ON releases.all_artists LIKE CONCAT('%', artist_love.artist, '%') AND artist_love.user = 'Quickinho' 
INNER JOIN label_love 
    ON releases.label_no_country = label_love.label AND label_love.user = 'Quickinho' 
INNER JOIN charts_extended as a 
    ON a.release_id = releases.id 
LEFT JOIN charts_extended as b 
    ON b.release_id = releases.id 
     AND b.artist IN (SELECT dj FROM dj_love WHERE user = 'Quickinho') 
     AND b.artist = 'Quickinho' 
WHERE 
    b.release_id IS NULL 

ORDER BY releases.date DESC