<?php
$con=mysql_connect("localhost","root","");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("dbjobsheets", $con);
$result = mysql_query ("select * from checklist union select * from checklistdailylogs;");
while($row = mysql_fetch_array($result));
我嘗試了所有在谷歌,但沒有運氣。我也嘗試了連接命令,並且我得到了mysql_fetch_array()的錯誤,期望參數1成爲資源。數組結果在我的UNION查詢中變爲0
提取數組仍存在錯誤。
$result = mysql_query ("select frequency from checklist union select daily from checklistdailylogs;");
我有沒有這方面的錯誤,但是當我嘗試添加另一列這樣
$result = mysql_query ("select frequency, sla from checklist union select daily, actualstart from checklistdailylogs;");
了mysql_fetch_array()預計參數1是資源。
寫入有效的sql'select checklistdailylogs' ?? – 2014-10-17 02:56:29
+1 ^^^ - 'while($ row = mysql_fetch_array($ result));'好吧,然後呢?分號在那裏停下。 – 2014-10-17 02:57:52
口渴,醉酒朗姆酒 – 2014-10-17 02:58:53