％像預期

Question

我工作的搜索功能，我根據用戶輸入查詢，但我沒有得到預期的結果查詢％不給結果

//if user searches walter getting proper response 

http://localhost:8000/api/v1/search/walter 

{ 
    "data": [ 
    { 
     "id": 1, 
     "first_name": "Walter", 
     "last_name": "White", 
     "phone_number": "9665885542", 
     "registration_id": "12345b67892" 
    }, 
    { 
     "id": 8, 
     "first_name": "Mitty", 
     "last_name": "Walter", 
     "phone_number": "8826835542", 
     "registration_id": "dffdfg54ty45y" 
    } 
    ] 
} 

// but if user searches walt the response is 

http://localhost:8000/api/v1/search/walt 

{ 
    "data": [] 
} 

我的方法

//搜索驅動程序 公共職能getSearchResults（$ SEARCH_INPUT）{

$search_drivers = Driver::where('id', 'like', $search_input) 
       ->orWhere('first_name', 'like', $search_input) 
       ->orWhere('last_name', 'like', $search_input) 
       ->orWhere('phone_number', 'like', $search_input) 
       ->orWhere('registration_id', 'like', $search_input) 
       ->select('id','first_name','last_name','phone_number','registration_id') 
       ->get(); 

return Response::json([ 
    'data' => $search_drivers 
]);  

}

有沒有更好的方式進入全數據

之前得到結果謝謝

Answer 1

爲like正確的語法是'%'.$search_input.'%'：

$search_drivers = Driver::where('id', 'like', '%'.$search_input.'%') 
    ->orWhere('first_name', 'like', '%'.$search_input.'%') 
    ->orWhere('last_name', 'like', '%'.$search_input.'%') 
    ->orWhere('phone_number', 'like', '%'.$search_input.'%') 
    ->orWhere('registration_id', 'like', '%'.$search_input.'%') 
    ->select('id','first_name','last_name','phone_number','registration_id') 
    ->get();