CUFFT庫作品CUDA 3，但給出了CUDA運行時錯誤無效值4

Question

我已經成功地使用了CUFFT庫CUDA 3，但相同的代碼將無法在CUDA 4.運行帶有CUDA 4，我得到一個運行時錯誤（CUDA_INVALID_VALUE ）執行FFT時。這是一個前向實到複雜的一維變換。我在CUDA 3和CUDA 4之間的CUFFT文檔中看到的唯一一件事是增加了FFTW兼容性模式。我將其設置爲純模式。

void mexFunction(int nlhs, mxArray *plhs[], 
       int nrhs, const mxArray *prhs[]) 
{ 
int Nfft, Navg, iAvg, N, n1, n2, Npsd, size[2]; 

float *hReal; 
float *pPxx; 

float *dReal; 
float *dAvg, *dSum, *dWindow; 
float U; 
long lAvg, lSum, lWindow; 
cufftHandle   hPlan; 
cufftComplex *dComplex; 
cufftResult result; 

int nBlocks, blockSize; 

if (nrhs == 12) 
{ 
Nfft =  mxGetScalar(prhs[0]); 
blockSize = mxGetScalar(prhs[1]); 
Navg =  mxGetScalar(prhs[2]); 
iAvg =  mxGetScalar(prhs[3]); 
U =   mxGetScalar(prhs[4]); 
n1 =  mxGetScalar(prhs[5]); 
n2 =  mxGetScalar(prhs[6]); 
hPlan =  (cufftHandle)mxGetScalar(prhs[7]); 
hReal =  (float *)mxGetData(prhs[8]); 
lWindow = (long)mxGetScalar(prhs[9]); 
lAvg =  (long)mxGetScalar(prhs[10]); 
lSum =  (long)mxGetScalar(prhs[11]); 
} 
else 
    mexErrMsgTxt("fftcuda: Function requires 12 inputs"); 

// pointers to GPU arrays 
dWindow = (float *)lWindow; 
dAvg = (float *)lAvg; 
dSum = (float *)lSum; 

// size of output array 
N = Nfft/2 + 1; 
Npsd = n2 - n1 + 1; 
size[0] = 1; 
size[1] = Npsd; 

/* Allocate working arrays on device */ 
cudaMalloc((void**)&dReal,sizeof(float)*Nfft); 
cudaMalloc((void**)&dComplex,sizeof(cufftComplex)*N); 

/* Copy input array to the device */ 
cudaMemcpy((void*)dReal,(void*)hReal,sizeof(float)*Nfft,cudaMemcpyHostToDevice); 

// setup for cuda functions 
nBlocks = (int)(Nfft/blockSize); 

/* multiply input array by window */ 
cudaMult <<< nBlocks, blockSize >>> (dReal,dWindow,dReal,Nfft); 

/* Execute FFT on device */ 
    result = cufftExecR2C(hPlan, (cufftReal *)dReal, dComplex); 

if (result == CUFFT_SETUP_FAILED) 
    mexErrMsgTxt("CUFFT library failed to initialize."); 
else if (result == CUFFT_INVALID_PLAN) 
    mexErrMsgTxt("The hPlan parameter is not a valid handle."); 
else if (result == CUFFT_INVALID_VALUE) 
    mexErrMsgTxt("The idata or odata parameter is not valid."); 
else if (result == CUFFT_EXEC_FAILED) 
    mexErrMsgTxt("CUFFT failed to execute the transform on GPU."); 

// setup for cuda functions 
nBlocks = (int)(Npsd/blockSize) + (Npsd%blockSize); 

/* Compute absolute value */ 
cudaAbs <<< nBlocks, blockSize >>> (&dComplex[n1-1],dReal,Npsd); 

if (nlhs != 1) 
    mexErrMsgTxt("fftcuda: Function requires 1 output: float pPxx"); 

plhs[0]=mxCreateNumericArray(2,size,mxSINGLE_CLASS,mxREAL); 

pPxx = (float *)mxGetData(plhs[0]); 

/* Copy result back to host */ 
cudaMemcpy((void*)pPxx, (void*)dReal, sizeof(float)*Npsd,cudaMemcpyDeviceToHost); 

/* free working arrays from gpu memory */ 
cudaFree((void*)dReal); 
cudaFree((void*)dComplex); 

return; 
} 

Answer 1

CUFFT庫不只有一個版本。由於CUFFT是CUDA工具包的一部分，因此隨CUDA Toolkit的每個新版本一起發佈該庫的更新版本。

如果你想使用該庫的舊副本與CUDA的新版本，這是幾乎可以肯定你的問題。只需使用與您的CUDA工具包相同版本的CUFFT，它就可以工作。