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我有一個帶自動前進功能的jQuery滑塊。但是我想知道如何在最後一張幻燈片到達後返回到第一張幻燈片。 currentSlide變量(保存我們正在查看的當前幻燈片的索引)只是越來越大,在到達最後一張幻燈片後不會返回零。我沒有將滑塊本身的所有jQuery腳本都包含進去,因爲這會很大,而且我覺得沒有必要。下面是代碼:在到達最後一張幻燈片後返回第一張幻燈片 - 使用jQuery Slider
<html>
<head>
</head>
<body>
<div class="slider" data-slide="0">
<div class="slide"></div>
<div class="slide"></div>
<div class="slide"></div>
<div class="slide"></div>
</div>
<script type="text/javascript" src="js/jquery-1.7.2.js"></script>
<script type="text/javascript">
$(window).load(function(){
var currentSlide = $(".slider").attr("data-slide"); /*Every time a slide is viewed, the index number of that slide is added to an html5 data- attribute. That way, we know what slide we are on. This var stores that information. */
var timeOut = null;
(function autoAdvance(){
$('.sliderNav').find('.sliderTrigger' + (currentSlide)).trigger('click',[true]); /* Automatically click the trigger that will advance the slider to the next slide. */
currentSlide++;
timeOut = setTimeout(autoAdvance,5000);
})();
});
</script>
</body>
</html>
非常感謝,我簡直不敢相信我沒想到!只有一個問題:你需要改變currentSlide = 1;到currentSlide = 0;因爲索引是基於零的。 –