在C中使用kbhit來控制機器人的BGI繪圖

我一直在嘗試各種組合的if和do語句，但無法使其正常工作。我們使用Visual Studio 2015並使用C代碼。代碼的總體目標是使用BGI圖形來模擬2D機器人（一個圓圈和一條線來指示方向），並使其執行各種任務。我被告知;在C中使用kbhit來控制機器人的BGI繪圖

修改您的程序，以便您可以用鍵盤控制您的機器人。

要做到這一點，您應該初始化初始速度爲0，並添加適當的語句到您的程序，以修改基於哪個鍵被按下的速度。舉例來說，你可以

固定不變量的增量v當UP鍵被按下固定不變量的

遞減v當DOWN鍵被按下

遞減W A固定不變量當右鍵被按下

增量瓦特固定恆定量的當左鍵被按下

使用另一個鍵來停止機器人

#include <graphics.h> // includes BGI functions 
#include <conio.h> 
#include <math.h> 
#include <stdio.h> 

int main() 
{ 
// this is a line of comment 
// initialise a 500 X 300 pixels viewport (2D graphic window) 
// don't modify the following lines of code 
int gd, gm; 
gd = CUSTOM; 
gm = CUSTOM_MODE(500, 300); 
initgraph(&gd, &gm, ""); 
int kbhit(), c = 0; 
float c1, c2, c3, c4, alpha, theta; 
int x, y, radius = 40, A, B; 
int xvTL = 0, yvTL = 0, xvBR = 500, yvBR = 300; 
int xTL = 0, yTL = 0, xBR = 50, yBR = 50; 
int xv, yv, W, H; 
float v, w, dt, beta, sigma; 
printf("Pixels of graph window (Bottom Right) = 500, 300. World coordinates (Bottom Right) set to 50, 50 \n");     
printf("Enter a number for x: \n"); 
scanf("%d", &x); 
printf("Enter a number for y: \n"); 
scanf("%d", &y); 
W = xBR - xTL; 
H = yTL - yBR; 
xv = (x - xTL) * (500/W); 
yv = (yTL - y) * (300/H); 
printf("Coordinates(in viewport) = %d, %d \n", xv, yv); 
printf("Enter an angle (in degrees) : \n"); 
scanf("%f", &alpha); 
theta = (float)alpha * 3.1416/180; 
printf("Angle (in radians) = %f \n", theta); 
A = cos(theta) * radius; 
B = sin(theta) * radius; 
if ((alpha = 90), (0 < alpha < 90), (90 < alpha < 180), (180 < alpha < 270), (alpha = 270), (270 < alpha < 360)) 
    (B = sin(theta) * -radius); 
else 
    (B = sin(theta) * radius); 
circle(xv, yv, radius); 
line(xv, yv, xv + A, yv + B); 
v = 0; 
w = 0; 
do { 
    clearviewport(); 
    dt = 2; 
    xv = xv + v * dt * cos(theta); 
    yv = yv + v * dt * sin(theta); 
    sigma = theta + dt * w; 
    beta = sigma * 180/3.1416; 
    A = cos(sigma) * radius; 
    B = sin(sigma) * radius; 
    if ((beta = 90), (0 < beta < 90), (90 < beta < 180), (180 < beta < 270), (beta = 270), (270 < beta < 360)) 
     (B = sin(sigma) * -radius); 
    else 
     (B = sin(sigma) * radius); 
    circle(xv, yv, radius); 
    line(xv, yv, xv + A, yv + B); 
    delay(200); 
    if (_kbhit()) { 
     (c = _getch()); 
    } 
    if (_kbhit()) { 
     c1 = ++v; 
     v = c1; 
    } 
    if (_kbhit()) { 
     c2 = --v; 
     v = c2; 
    } 
    if (_kbhit()) { 
     c3 = ++w; 
     w = c3; 
    } 
    if (_kbhit()) { 
     c4 = --w; 
     w = c4; 
    } 
} while (c != KEY_ESCAPE); (c1 = KEY_UP); (c2 = KEY_DOWN); (c3 = KEY_LEFT); (c4 = KEY_RIGHT); 

return 0; 
}

來源

2017-03-01 EllieC

你想要一個調用kbhit（）。假設傳統功能，它會告訴你在通話時是否按下了一個按鍵。所以你只想在你的循環中調用它一次。

if(kbhit()) 
{ 
    ./* action to alter robot */ 
} 
else 
{ 
    /* no user moves, maybe robot still has momentum */ 
}

嘗試將某些邏輯移出main（）以及。

來源

2017-03-01 23:12:30

在C中使用kbhit來控制機器人的BGI繪圖

回答

相關問題