Oracle SQL - 不是GROUP BY函數

我正在嘗試使用一個非常簡單的查詢來選擇ID號，名稱，2個日期，這些日期之間的日期以及視圖中幾項成本的總和。Oracle SQL - 不是GROUP BY函數

但是無論我如何鼓搗它，我所得到的都是這個錯誤。

我知道我不是那種過分熱情，但我真的不知道怎麼回事錯了（我有點真新本）。在此先感謝，代碼如下。

SELECT vw.RESERVATION_NUMBER AS "Reservation Number" 
     , owner.OWNER_FIRST_NAME || ', ' || owner.OWNER_LAST_NAME AS "Owner Name" 
     , vw.RESERVATION_START_DATE AS "Start Date" 
     , vw.RESERVATION_END_DATE AS "End Date" 
     , vw.RESERVATION_END_DATE - vw.RESERVATION_START_DATE AS "Number of Days" 
     , SUM(vw.DAILY_RATE) AS "Invoice Total" 
FROM HVK_RESERVATION_CHARGES_VW vw, HVK_OWNER owner 
WHERE owner.OWNER_NUMBER = vw.OWNER_NUMBER 
AND vw.RESERVATION_NUMBER = vw.RESERVATION_NUMBER 
GROUP BY vw.RESERVATION_NUMBER;

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2014-12-11 Duncan McKirdy

把所有的領域從group by子句中select聲明未包含在聚合：

... 
GROUP BY vw.RESERVATION_NUMBER, 
     owner.OWNER_FIRST_NAME || ', ' || owner.OWNER_LAST_NAME, 
     vw.RESERVATION_START_DATE, 
     vw.RESERVATION_END_DATE

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2014-12-11 03:41:55 sgeddes

在Oracle（與大多數數據庫），你必須全部聚集沒有聚合函數列：

SELECT vw.RESERVATION_NUMBER AS "Reservation Number", 
     owner.OWNER_FIRST_NAME || ', ' || owner.OWNER_LAST_NAME AS "Owner Name", 
     vw.RESERVATION_START_DATE AS "Start Date", vw.RESERVATION_END_DATE AS "End Date", 
     (vw.RESERVATION_END_DATE - vw.RESERVATION_START_DATE) AS "Number of Days", 
     SUM(vw.DAILY_RATE) AS "Invoice Total" 
FROM HVK_RESERVATION_CHARGES_VW vw JOIN 
    HVK_OWNER owner 
    ON owner.OWNER_NUMBER = vw.OWNER_NUMBER AND vw.RESERVATION_NUMBER = vw.RESERVATION_NUMBER 
GROUP BY vw.RESERVATION_NUMBER, owner.OWNER_FIRST_NAME || ', ' || owner.OWNER_LAST_NAME, 
     vw.RESERVATION_START_DATE, vw.RESERVATION_END_DATE;

然而，由於所有的聚集列，我不是很確定聚集甚至不需要爲此QUER年。

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2014-12-11 03:42:35

其他人已經識別出導致編譯失敗的語法錯誤。所以我會指出你的代碼中的邏輯失敗：你寫的東西並不計算停留的成本。你需要通過每天的房費乘以天數：

(vw.RESERVATION_END_DATE - vw.RESERVATION_START_DATE) 
       * vw.DAILY_RATE AS "Invoice Total"

這意味着你不需要SUM（），所以你可以用GROUP完全免除BY子句。

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2014-12-11 05:30:31 APC

Oracle SQL - 不是GROUP BY函數

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